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Zinaida [17]
3 years ago
12

Help broooo math suckssss​

Mathematics
2 answers:
tatuchka [14]3 years ago
7 0

Answer:

<BOA

Step-by-step explanation:

60°- 40°= 20°

40°+20°=60°

astra-53 [7]3 years ago
4 0

Answer:

the answer is BOA

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What is the slope of a line that contains the points (12,17) and (-8,-17)
professor190 [17]
\frac{y2 - y1}{x2 - x1}
\frac{ - 17 - 17}{ - 8 - 12} = \frac{ - 34}{ - 20} = \frac{17}{10}
Alternative forms:
1 \frac{7}{10} \: or \: 1.7
Slope: 17/10
Equation : y= 17/10x
6 0
4 years ago
Look at this graph.
Phoenix [80]

Answer:  y= 1/4 x + 500

Step-by-step explanation:

The slope is the difference in y-values divided by difference in x-values plus the starting constant value (500 on the graph)

700 - 600  is the difference in y-values = 100

800 - 400 is the difference in x-values  = 400

100/400 = 1/4

y = x/4 +500

7 0
3 years ago
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Inessa [10]

Answer:

y=-1

Step-by-step explanation:

it is a straight line graph with no gradient therefore no X value. It crosses the y axis at -1

8 0
3 years ago
What is the speed that a car reaches in m/s, if it travels 956km in 56sec?Help me!! MRU (Uniform Rectilinear Movement)
In-s [12.5K]

Answer:

17.07m/s

Step-by-step explanation:

v=d/t

d=956km

t=56sec

v=956/56

v=17.07m/s

8 0
3 years ago
Joaquin is constructing the perpendicular bisector of ab. What should be his first step?
natali 33 [55]

Answer:

D. Open the compass so that the distance from the two points of the compass is wider than half the length of \over{AB}.

Step-by-step explanation:

To construct a perpendicular for \over{AB}, we must first take a compass & take the distance of its arms wider than half the length of \over{AB}.

This is done in order to get two intersecting arcs in the top & bottom of \over{AB} so that a perpendicular bisector can be drawn through it.

After two intersecting lines are drawn below & above \over{AB}, draw a line joining these 2 points through their points of intersection. The point where it intersects \over{AB} is the middle-most point of \over{AB} & now a perpendicular bisector of \over{AB} is constructed.

\rule{150pt}{2pt}

3 0
2 years ago
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