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storchak [24]
3 years ago
14

Helpppppp guyssss pleaseeeeeee I’m losttt

Mathematics
1 answer:
Nimfa-mama [501]3 years ago
3 0

Answer:

29

Step-by-step explanation:

Use definition of conditional probability:

P(A|B)=\dfrac{P(A\cap B)}{P(B)},

where

A = the student is a freshman,

B = the student is a male

From the table,

P(B)=\dfrac{4+6+2+2}{4+6+2+2+3+4+6+3}=\dfrac{14}{30}=\dfrac{7}{15}\\ \\P(A\cap B)=\dfrac{4}{4+6+2+2+3+4+6+3}=\dfrac{4}{30}=\dfrac{2}{15}

So,

P(A|B)=\dfrac{\frac{2}{15}}{\frac{7}{15}}=\dfrac{2}{7}\approx 0.29=29\%

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Triangle XYZ has vertices X(0,3), Y(2,0) and Z(4,2). if yo reflect triangle XYZ across the line x=4, what will be the coordinate
Paha777 [63]

As X' is the reflected point of X(0,3) , so the x co ordinate of X' = 0+8 =8 and here y co ordinate remains same.

So, X'= (8,3)

Like that way, Y' is the reflected point of Y(2,0) and Z' is the reflected point of Z(4,2)

As the point Z is lying on the line x=4 and the reflection is also across that line, so both Z and Z' represent same point.

Y'= (2+4, 0) = (6, 0)

Z' = (4, 2)

3 0
3 years ago
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dalvyx [7]

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Answer:

  2

Step-by-step explanation:

Fill in the argument value and look up the function value on the graph.

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7 0
2 years ago
Mustafa’s horse ate 6,400 pounds of hay last year. How could Mustafa determine the number of tons of hay his horse ate last year
Alex

Answer: 3.2 tons

Step-by-step explanation:

We know that 1 ton = 2000 pound

Then , \text{1 pound}=\dfrac{1}{2000}\text{ ton}

Given : Mustafa’s horse ate 6,400 pounds of hay last year.

Then, the number of tons of hay his horse ate last year is given by :-

6400\times\dfrac{1}{2000}\ \ \text{ tons}\\\\=3.2 \text{ tons}

Therefore, the  number of tons of hay his horse ate last year = 3.2 tons

5 0
3 years ago
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elena55 [62]
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3 years ago
There are three identical desks, each with two drawers. In one desk, both drawers contain gold coins. In another desk, both draw
djverab [1.8K]

Answer:

P ( B / A ) = 1/3

Step-by-step explanation:

Solution:-

You select a drawer and select a coin from that drawer.

Let A denote the event that the coin that you select is silver.

Let B denote the event that the other coin in the drawer is gold.

You are equally likely to pick any coin, so:

                 P ( A ) = 3 silver coins / 6 coins in total = 0.5

There are 6 different ways you could have selected a coin. Only one of them results in you selecting a silver coin AND the other coin in the drawer being gold, so:

                 P ( A & B ) = 1 desired / 6 total coins = 1/6

By the definition of conditional probability:

                P ( B / A ) = P ( A & B ) / P ( A )

                                 = 1/6 / 0.5

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5 0
3 years ago
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