A) Possible outcomes are ...
(1, 3), (1, 4), (2, 2), (2, 3), (3, 1), (3, 2), (4, 1)
for a total of 7 out of 36 outcomes that match your requirements.
p(3 < sum ≤ 5) = 7/36
B) Possible outcomes are ...
(6, 1), (6, 3), (6, 5), (1, 6), (3, 6), (5, 6)
for a total of 6 out of 36 outcomes that match your requirements.
p(6 and odd) = 6/36 = 1/6
Answer:
Step-by-step explanation:
Chance of picking a house 1 year old is 17%
Chance of picking a house 2 years old is 22%
Chance of picking a house 3 years old is 28%
Chance of picking a house 4 years old is 33%
The only graph most fitting is the top graph of the first answer choice picture or:
Answer:
Need a picture of the problem.
Step-by-step explanation:
Answer:
Option A , (0, 20); y equals one over eighty times x squared plus 20
Step-by-step explanation:
The equation of parabola is given by
(X-h)^2 = 4p(Y-k)^2
In this case h = 0
So we get
Y = X^2/4P +k
Focus point is (h, p+k) , p+k = 40
Hence h, k = (0,20)
P = 40-k = 20
Equation Y = X^2/80 +20
Hence, option A is correct
Answer:
you can divide both of the numbers
Step-by-step explanation:
