Answer:
Rate = $33
Maximum Income = $5445
Explanation:
Let x be the amount of increase in rental to achieve maximum profit.
So, Rate = (30+x)
When rate increase by x, the quantity decreases by (180 -5x).
Income = (30+x) * (180 - 5x)
Income = 5400 - 150x + 180x - 5x²
Income = -5x² + 30x + 5400
The income will be maximized when derivative of Income is zero.
Taking derivative,
- dI/dx = 2 * -5x + 1 * 30x° + 0
- -10x + 30 = 0
- -10x = -30
- x = -30 / -10
- x = 3
The rate at which cars should be rented to earn maximum income is 30 + 3 = $33 per day per car.
Maximum Income will be,
Rate = 33
Quantity = 180 - 5(3) = 165 cars
Max Income = 33 * 165 = $5445
Answer: Cross price elasticity is - 0.12
Explanation:
Cross price elasticity measures the responsiveness of quantity demanded of good a to a change in any of its related variable such as good b.

Given,
Pa=6, Pb=3, and M=30,



So, cross price elasticity is given by



Since, cross price elasticity is negative it means that good a and good b are complements to each other.
Answer:
Path A-F-G-H is the critical path
Explanation:
Path A-F-G-H is the longest path on the network with length of 30 days. A path with the longest length is the critical path.
Answer:
d. 1.05 kilograms
Explanation:
Since we are looking for the standard quatity in kilograms of input per unit of out put we are going to sum up all the input for each unit of output in order to arrived at the standard quantity in kilograms.
Output unit required 0.92 kg
Add: waste and spoilage allowance 0.02 kg
Allowance rejected 0.11 kg
Standard quantity in kilograms 1.05 kg