If a polynomial has one root in the form a + the square root of B it has a second root in the form of a _ square root of b.
2 answers:
Answer:
Step-by-step explanation:
It's important to know that where roots of a polynomial involves radical roots, it does as conjugates. That is, the roots have the same terms but with a opposite middle sign between.
So, in this case, we have one root , which involves a root and a positive sign. To complete the conjugate behaviour, the other roots has to have the same terms but with different sign between, that is
Therefore, the answer that completes the given statement is
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In accordance with <em>propositional</em> logic, <em>quantifier</em> theory and definitions of <em>simple</em> and <em>composite</em> propositions, the negation of a implication has the following equivalence:
(Correct choice: iii)
<h3>How to find the equivalent form of a proposition</h3>
Herein we have a <em>composite</em> proposition, that is, the union of <em>monary</em> and <em>binary</em> operators and <em>simple</em> propositions. According to <em>propositional</em> logic and <em>quantifier</em> theory, the negation of an implication is equivalent to:
To learn more on propositions: brainly.com/question/14789062
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we have given y interms of x.
we have given that add 2 to x.
which means
so we have .
so when x.
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