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svlad2 [7]
2 years ago
12

Which is cheaper for a $65 item that costs $7.24 to ship? A 10% coupon off the cost of the item or free shipping (10 points)

Mathematics
2 answers:
Komok [63]2 years ago
7 0
If we are finding 10% the cost of the item
you would set a proportion
or an easier way would be 
.10x65
6.5
then you subtract that from 65
65-6.5
58.50 is the cost of the item 10% off but with shipping, it would be
58.50+7.25
65.75 is when there is 10% of the item
but it is $65 only if the shipping is free
and since 65<65.75
It is cheaper when the shipping is free

Fittoniya [83]2 years ago
6 0

Answer: Yes, 10% coupon.

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A golfer hits an errant tee shot that lands in the rough. A marker in the center of the fairway is 150 yards from the center of
Gwar [14]

\bold{\huge{\underline{ Solution}}}

<h3><u>Given </u><u>:</u><u>-</u></h3>

  • A marker in the center of the fairway is 150 yards away from the centre of the green
  • While standing on the marker and facing the green, the golfer turns 100° towards his ball
  • Then he peces off 30 yards to his ball

<h3><u>To </u><u>Find </u><u>:</u><u>-</u></h3>

  • <u>We </u><u>have </u><u>to </u><u>find </u><u>the </u><u>distance </u><u>between </u><u>the </u><u>golf </u><u>ball </u><u>and </u><u>the </u><u>center </u><u>of </u><u>the </u><u>green </u><u>.</u>

<h3><u>Let's </u><u> </u><u>Begin </u><u>:</u><u>-</u></h3>

Let assume that the distance between the golf ball and central of green is x

<u>Here</u><u>, </u>

  • Distance between marker and centre of green is 150 yards
  • <u>That </u><u>is</u><u>, </u>Height = 150 yards
  • For facing the green , The golfer turns 100° towards his ball
  • <u>That </u><u>is</u><u>, </u>Angle = 100°
  • The golfer peces off 30 yards to his ball
  • <u>That </u><u>is</u><u>, </u>Base = 30 yards

<u>According </u><u>to </u><u>the </u><u>law </u><u>of </u><u>cosine </u><u>:</u><u>-</u>

\bold{\red{ a^{2} = b^{2} + c^{2} - 2ABcos}}{\bold{\red{\theta}}}

  • Here, a = perpendicular height
  • b = base
  • c = hypotenuse
  • cos theta = Angle of cosine

<u>So</u><u>, </u><u> </u><u>For </u><u>Hypotenuse </u><u>law </u><u>of </u><u>cosine </u><u>will </u><u>be </u><u>:</u><u>-</u>

\sf{ c^{2} = a^{2} + b^{2} - 2ABcos}{\sf{\theta}}

<u>Subsitute </u><u>the </u><u>required </u><u>values</u><u>, </u>

\sf{ x^{2} = (150)^{2} + (30)^{2} - 2(150)(30)cos}{\sf{100°}}

\sf{ x^{2} = 22500 + 900 - 900cos}{\sf{\times{\dfrac{5π}{9}}}}

\sf{ x^{2} = 22500 + 900 - 900( - 0.174)}

\sf{ x^{2} = 22500 + 900 + 156.6}

\sf{ x^{2} = 23556.6}

\bold{ x = 153.48\: yards }

Hence, The distance between the ball and the center of green is 153.48 or 153.5 yards

5 0
2 years ago
Please help me if you can. Please also write how you got the answer thank you.
adelina 88 [10]

Answer:

1) r, q, s. 2). 5

Step-by-step explanation:

1) from the given (q) is smaller than (r) and (s) is less than (q) by 2.

2) you need to make all the fractions have the same numerator so you will multiply both the firs and third fraction by 3÷3 ( which is 1 and will not affect the value but will make the numerator of the fractions equal) and the fractions between them is the second fraction and it's denominator is x and there is 5 fractions between the two numbers so there are 5 possible values of x

6 0
2 years ago
Knut had picked strawberries during the summer holidays. First days he picked 9090 baskets of strawberries! The next day he was
jasenka [17]

Answer:

190 baskets of strawberries

Step-by-step explanation:

The question is incomplete as it didn't state what we are to determine from the information given.

Let's determine total amount picked in the three days.

1st day picked 90strawberries

Amount of strawberries on 2nd day = 2/3 of the amount picked 1st day

= (2/3)(90)

Amount of strawberries on 2nd day = 60 baskets of strawberries

Amount of strawberries picked on 3rd day = (2/3) of the amount picked 2nd day

= (2/3) (60)

Amount of strawberries picked on 3rd day = 40 basket of strawberries

Total amount picked for 3 days = 90+60+40

= 190 baskets of strawberries

4 0
3 years ago
Go to it WEAKLINGS if you are brave enough that is
Olegator [25]

Answer:

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Step-by-step explanation:

8 0
2 years ago
The net of a rectangular prism is shown below.
Mamont248 [21]

Answer:

28

Step-by-step explanation:

Using a net to find the surface area of a rectangular prism

Finding the areas of each of the rectangles and squares of the net of a rectangular prism and adding up those areas gives the surface area or total surface area of the prism.

For example, if the length of one side of the cube 4 units then the area of one its face is 4 × 4 = 16 square units. From the net, we can see that there are six equal faces and so we get the total surface area is 6 × 16 = 96 square units.

Surface Area of a Rectangular Prism using Nets

A rectangular prism or cuboid is formed by folding a net as shown −

Cuboid

We can see from the net that there are two rectangles with dimensions 3 cm by 6 cm, two rectangles with dimensions 2 cm by 6 cm and two rectangles with dimensions 2 cm by 3 cm. The total surface area is then

2 × 3 × 6 + 2 × 2 × 6 + 2 × 2 × 3 = 72 cm2

Example 1:

Find the surface area of the given rectangular prism in square cm.

Rectangular Prism in Square cm

Solution

Step 1:

Using net, the surface area of a rectangular prism

= 2lw+wh+lh; l = 6 ; w = 5; h = 3

Step 2:

Surface area of given prism = 26×5+6×3+3×5

= 230+18+15

= 126 square cm

Example 2:

Find the surface area of the given rectangular prism in square cm.

Rectangular Prism Square cm

Solution

Step 1:

Using net, the surface area of a rectangular prism

= 2lw+wh+lh; l = 5; w = 6; h = 4

Step 2:

Surface area of given prism = 25×6+5×4+6×4

= 230+20+24

= 148 square cm

6 0
2 years ago
Read 2 more answers
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