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mariarad [96]
3 years ago
10

PLEASE HELP ON THIS QUESTION......... THANK U

Mathematics
2 answers:
dexar [7]3 years ago
8 0
A is the answer.  Ask if you need me to explain.
slega [8]3 years ago
3 0
I think the answer is the first one f(x) = 90x + 130
50 + 40 = 90   50 + 80 = 130
Hope it helps

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Two cities are building bicycle paths. Charles City has built 5km of bicycle paths by the end of the first month, and the total
sergey [27]

Answer:

Month 4

Step-by-step explanation:

To solve this problem we must propose an equation that models the number of kilometers of bicycle trails made monthly in Charles City and in Tinsel Town

<em>For Charles City </em>we know that the number of kilometers built in the first month is 5, and it doubles every month. Then we have an exponential equation, in base 2, whose initial value is 5.

This equation has the following form:

y = C_1 (2^{x-1})

Where:

C_1 is the number of kilometers built in month 1

x is the number of months: {1, 2, 3, 4, 5 ... x}

x = 1 represents month 1.

So:

Charles\ City\ (km) = 5(2^{x-1})

<em>For Tinsel Town</em> we know that the number of kilometers built in the first month is 21 and increases at a fixed rate of 5 kilometers per month. This can be modeled by a linear equation.

Tinsel\ Town\ (km) = 21 + 5(x-1)

Where x is the number of months. x: {1, 2, 3, 4, 5 ...}

We want to know at the end of what month the total length of the cycle lanes in Charles City first exceeds the length in Tinsel Town

Then we equal both equations and clear x.

5 (2^{x-1}) = 21 + 5(x-1)\\\\5 (2^{x-1}) - (21 + 5(x-1)) = 0

Clearing x from this equation is very difficult, so to find x, we iterate until we get the value of x that causes the equation to approach 0.

For x = 3

5(2^{3-1}) - (21 +5(3-1)) = 0\\\\20- 31= -11

For x = 4

5(2^{4-1}) - (21 +5(4-1)) = 0\\\\40 - 36 = 4

<em>The value must be between x = 3 and x = 4</em>

For x = 3.8

5 (2^{3.8-1}) - (21 +5(3.8-1)) = 0\\\\34.82 - 35 = 0.18

Then x ≈ 3.8 months.

Finally we have that By the end of the fourth month the total length of the cycle lanes in Charles City exceeds the length in Tinsel Town

6 0
4 years ago
I cant do this pls help
KengaRu [80]
The distance is 5. Hope this helps!

4 0
3 years ago
Read 2 more answers
Find the complement of the set given that
iris [78.8K]

Answer:

A ' = {-2,-1,0,1, 4,7}

Step-by-step explanation:

Here, the Universal set U is given as:

U = {x | x is in I and −3 ≤ x ≤ 7}

⇒ U = { -3,-2,-1,0,1,2,3,4,5,6,7}

Now given: A = {−3, 2, 3, 5, 6}

Compliment  A set of any set A is the set of all the elements which is in the universal set U but NOT in A.

So, here the set of elements which are in U but not in A  is

A ' = {-2,-1,0,1, 4,7}

So here the elements in the compliment of the given set -2,-1,0,1,4,7

4 0
3 years ago
If 12x + 3 - 4x - 3 = 8, then x = ?
iVinArrow [24]
12x - 4x = 8 + 3 - 3
8x = 8
X = 1
5 0
3 years ago
Factor both quadratic expressions. (x 4 + 5x 2 - 36)(2x 2 + 9x - 5) = 0
Sonbull [250]

So focusing on x^4 + 5x^2 - 36, we will be completing the square. Firstly, what two terms have a product of -36x^4 and a sum of 5x^2? That would be 9x^2 and -4x^2. Replace 5x^2 with 9x^2 - 4x^2: x^4+9x^2-4x^2-36

Next, factor x^4 + 9x^2 and -4x^2 - 36 separately. Make sure that they have the same quantity inside of the parentheses: x^2(x^2+9)-4(x^2+9)

Now you can rewrite this as (x^2-4)(x^2+9) , however this is not completely factored. With (x^2 - 4), we are using the difference of squares, which is a^2-b^2=(a+b)(a-b) . Applying that here, we have (x+2)(x-2)(x^2+9) . x^4 + 5x^2 - 36 is completely factored.

Next, focusing now on 2x^2 + 9x - 5, we will also be completing the square. What two terms have a product of -10x^2 and a sum of 9x? That would be 10x and -x. Replace 9x with 10x - x: 2x^2+10x-x-5

Next, factor 2x^2 + 10x and -x - 5 separately. Make sure that they have the same quantity on the inside: 2x(x+5)-1(x+5)

Now you can rewrite the equation as (2x-1)(x+5) . 2x^2 + 9x - 5 is completely factored.

<h3><u>Putting it all together, your factored expression is (x+2)(x-2)(x^2+9)(2x-1)(x+5)=0</u></h3>
5 0
3 years ago
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