-5.8c+4.2-3.1+1.4c combine like terms to create an equivalent expression
2 answers:
<h2>Answer:</h2>
The equivalent expression to the given expression is:
We are given an algebraic equation in terms of the variable c as follows:
Now, we will first combine the like term i.e. the terms with the same variable term and the constant terms are combined altogether i.e. the expression is given as follows:
On simplifying this expression we get :
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Try this option:
1. Common view of hyperbola equation is:
2. hyperbolas are: 2x²+4x-5y²-10y+57=0 and -x²+12x+3y²+7y+11=0.
1. Common view of hyperbola equation is:
2. hyperbolas are: 2x²+4x-5y²-10y+57=0 and -x²+12x+3y²+7y+11=0.
Answer:
Part A.
Let f(x) = 0;
suppose x= a+h
such that f(x) =f(a+h) = 0
By second order Taylor approximation, we get
f(a) + hf'±(a) + f''(a) = 0
±
So, we get the succeeding equation for Newton's method as
±
Part B.
It is evident that Newton's method fails in two cases, as:
1. if f''(x) = 0
2. if f'(x)² is less than 2f(x)f''(x)
Part C.
In case is close to
, the choice that shouldbe made instead of ± in part A is:
f'(x) = ⇔
Part D.
As given =
= h
or h = -
We get,
f(a) + hf'(a) +(h²/2)f''(a) = 0
or h² = -hf(a)/f'(a)
Also, (-
)² = -(
-
)(f(
)/f'(
))
So, f(a) + hf'(a) - (f''(a)/2)(hf(a)/f'(a)) = 0
It becomes h = -f(a)/f'(a) + (h/2)[f''(a)f(a)/(f(a))²]
Also, =
-f(
)/f'(
) + [(
-
)f''(
)f(
)]/[2(f'(
))²]
Answer:
Step-by-step explanation:
Given
Required
Probability of selecting 2 toys of different types
From the question, we understand that all toys are different i.e. 1 of each type.
And the selection is without replacement;
So, after the first toy is selected; there are n - 1 toys left.
So, the probability is:
Substitute