Answer:
The speed of the man is 4.54 m/s.
Explanation:
Given that,
Mass of man=8100 g
Mass of stone = 79 g
Speed = 4.5 m/s
We need to calculate the speed of the man
Using momentum of conservation
Where,
=mass of man
=mass of stone
=velocity of man
=velocity of stone
Put the value in the equation
As the stone is away from the man
So, the speed of stone is zero
Hence, The speed of the man is 4.54 m/s.
Given:
mass is 3.1 kilograms
The acceleration due to gravity
is 9.8m/s2
Required:
Weight
Solution:
W = mg
W = (3.1 kilograms)( 9.8m/s2)
W = 30.38 Newtons
Answer:
Explanation:
Given:
- mass of the oscillator,
- first case of displacement,
- velocity in the first case,
- second case of displacement,
- velocity in the second case,
<u>Now as we know that the total energy in both the cases will remain conserved:</u>
Now the total energy:
When the whole of the spring potential converts into kinetic energy:
There are some missing data in the text of the exercise. Here the complete text:
"<span>A sample of 20.0 moles of a monatomic ideal gas (γ = 1.67) undergoes an adiabatic process. The initial pressure is 400kPa and the initial temperature is 450K. The final temperature of the gas is 320K. What is the final volume of the gas? Let the ideal-gas constant R = 8.314 J/(mol • K). "
Solution:
First, we can find the initial volume of the gas, by using the ideal gas law:
</span>
<span>where
p is the pressure
V the volume
n the number of moles
R the gas constant
T the absolute temperature
Using the initial data of the gas, we can find its initial volume:
</span>
<span>
Then the gas undergoes an adiabatic process. For an adiabatic transformation, the following relationship between volume and temperature can be used:
</span>
<span>where </span>
for a monoatomic gas as in this exercise. The previous relationship can be also written as
where i labels the initial conditions and f the final conditions. Re-arranging the equation and using the data of the problem, we can find the final volume of the gas:
So, the final volume of the gas is 310 L.