A 0.12 kg body undergoes simple harmonic motion of amplitude 8.5 cm and period 0.20 s. (a) What is themagnitude of the maximum f
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Answer:
Since the weight cannot take a negative value, it is concluded that the minimum weight required for the gate is zero, because the same pressure force will rotate the gate.
Explanation:
Given:
L = 12 m
F = 60 kN
w = 4 m
H = 9 m
The pressure force is:
The center of pressure is:
If the moment is equal to zero,
We can use the conservation of energy to solve this problem.
We know the bullet goes in at 39m/s and leaves with 27m/s and some energy lost. We can model this using the kinetic equation energy.
The "U" is the energy lost when the bullet went through the bag. Solving for U, we get:
Next we know the bag is 48cm thick and that F*d=W, rearranging this equation we get:
F = 12.375N
We know the bullet goes in at 39m/s and leaves with 27m/s and some energy lost. We can model this using the kinetic equation energy.
The "U" is the energy lost when the bullet went through the bag. Solving for U, we get:
Next we know the bag is 48cm thick and that F*d=W, rearranging this equation we get:
F = 12.375N