-- The boiling points of the first group are all at temperatures
that are way lower than a comfortable room.
. . . . . Nitrogen . . . -320° F
. . . . . Helium . . . . -452° F
. . . . . Neon . . . . . -411° F
The freezing points of the second group are all at temperatures
that are way higher than a comfortable room.
. . . . . Lithium. . . . . . 357° F
. . . . . Sodium . . . . . 208° F
. . . . . Potassium . . . 146 °F
Answer:
2.09 rad/s
Explanation:
Given that,
A toy car makes 4 laps in 12 s.
We need to find the angular velocity of the toy car. We need to find the angular velocity of the toy car.
4 laps = 25.13 rad
So,

So, the angular velocity of the toy car is 2.09 rad/s.
Answer:
Magnitude = 3.64 ×
စ = 43.9°
Explanation:
given data
ship to travel = 1.7 ×
kilometers
turn = 70°
travel an additional = 2.7 ×
kilometers
solution
we will consider here
Px = 1.7 ×
Py = 0
Qx =2.7 ×
cos(70)
Qy= 2.7 ×
sin(70)
so that
Hx = Px + Qx ............1
Hx = 2.62 ×
and
Hy = Py + Qy ..........2
Hy = 2.53 ×
so Magnitude = 
Magnitude = 3.64 ×
so direction will be
tan စ = Hy ÷ Hx ......................3
tan စ =
tan စ = 0.9656
စ = 43.9°
Answer:
100m
Explanation:
100m
s=ut+1/2at^2
s= unknown, u=0, a=2, t=10
s=0*10+1/2(2)(10)^2
s=1/2(2)(100)
s=1(100)
displacement = 100 meters
A variable is a letter so just be like
13a or something like that