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Brrunno [24]
2 years ago
8

A container of gas is held at a constant volume. Which will most likely happen to the temperature if the pressure of the gas inc

reases?
The temperature will increase at the same rate as the pressure increases.

The temperature will decrease at the same rate as the pressure increases.

The temperature will increase at half the same rate as the increase in pressure.

The temperature will decrease at half the same rate as the increase in pressure.​
Physics
1 answer:
sergij07 [2.7K]2 years ago
5 0

Answer:

With more particles there will be more collisions and so a greater pressure. The number of particles is proportional to pressure, if the volume of the container and the temperature remain constant. ... This happens when the temperature is increased.

Explanation:

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A train is traveling away from you at 120 km/h. it blows its whistle, and you hear a tone of 0.400 kHz. Take the speed of sound
Vaselesa [24]

Answer:B)439.21 Hz

Explanation:

Given

velocity of train v=120 km/h\approx 120\times \frac{5}{18}=33.33 m/s

frequency of train f_a=0.400 kHz\approx 400 Hz

speed of sound c=340 m/s

frequency from Doppler effect can be calculated by

f_a=(\frac{c}{c+v})\cdot f

400=(\frac{340}{340+33.33})\cdot f

400=\frac{340}{373.33}\cdot f

f=400\times 1.098

f=439.21 Hz

5 0
3 years ago
After crossing the finish line, a race car slows down from 47 m/s to 32m/s in 3seconds. What is the car’s acceleration?
Lisa [10]

Answer: -5 m/s^2

Explanation: a = v - u/t

                         = 32 - 47/3

                         = -15/3

                         = -5 m/s^2

7 0
3 years ago
Three charged particles are positioned in the xy plane: a 50-nC charge at y = 6 m on the y axis, a −80-nC charge at x = −4 m on
disa [49]

Answer:

V = 48 Volts

Explanation:

Since we know that electric potential is a scalar quantity

So here total potential of a point is sum of potential due to each charge

It is given as

V = V_1 + V_2 + V_3

here we have potential due to 50 nC placed at y = 6 m

V_1 = \frac{kQ}{r}

V_1 = \frac{(9\times 10^9)(50 \times 10^{-9})}{\sqrt{6^2 + 8^2}}

V_1 = 45 Volts

Now potential due to -80 nC charge placed at x = -4

V_2 = \frac{kQ}{r}

V_2 = \frac{(9\times 10^9)(-80 \times 10^{-9})}{12}

V_2 = -60 Volts

Now potential due to 70 nC placed at y = -6 m

V_3 = \frac{kQ}{r}

V_3 = \frac{(9\times 10^9)(70 \times 10^{-9})}{\sqrt{6^2 + 8^2}}

V_3 = 63 Volts

Now total potential at this point is given as

V = 45 - 60 + 63 = 48 Volts

3 0
3 years ago
NEED HELP ASAP PLEASE
Zarrin [17]

Answer:

D. 3.0 m/s

Explanation:

because I did this in my class

8 0
3 years ago
A new company is making security cameras. These security cameras will be different than other security cameras because instead o
babunello [35]

Answer:

b

Explanation:

4 0
2 years ago
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