The electrical conductivity of a conductor increases with increasing temperature
An electrical current flows through a conductor because it provides little to no resistance to the movement of electrons. Typically, good electrical conductors include metals, metal alloys, electrolytes, even some nonmetals like graphite and liquids like water.
Metals, aqueous salt solutions (ionic chemicals dissolved in water), graphite, and the human body are a few examples of conductors.
A conductor makes it simple for current to flow through it. Insulators prevent electricity from passing through them. On the surface of conductors, there is an electric charge. In an insulator, there are no electric charges. Keeping conductors in a magnetic field prevents them from storing energy.
To learn more about conductors please visit -
brainly.com/question/8426444
#SPJ4
Answer:
1. use a ruler to measure how many heights the ball falls down.
2. use notes to record observations.
<u>Answer:</u>
<em>To raise the pH of the solution to 3.10 we have to add 2.34 L of water.</em>
<u>Explanation:</u>
<em>Given that the pH of the solution of HCl in water is 2.5.</em> Here the solution’s pH is changing from 2.5 to 3.10 which means the acidic nature of the solution is decreasing here on dilution. ![[H^+]](https://tex.z-dn.net/?f=%5BH%5E%2B%5D)
ions contribute to a solution’s acidic nature and ![[OH^-]](https://tex.z-dn.net/?f=%5BOH%5E-%5D)
contribute to a solution’s basic nature.
The equation connecting the concentration of and pH of a solution is pH= ![-log[H^+]](https://tex.z-dn.net/?f=-log%5BH%5E%2B%5D)
<em>![[H^+]= 10^(^-^p^H^)](https://tex.z-dn.net/?f=%5BH%5E%2B%5D%3D%2010%5E%28%5E-%5Ep%5EH%5E%29)
![[H^+]= 10^(^-^2^.^5^)=0.00316](https://tex.z-dn.net/?f=%5BH%5E%2B%5D%3D%2010%5E%28%5E-%5E2%5E.%5E5%5E%29%3D0.00316)
</em>
<em>When the pH is ![3.1 [H^+ ]= 10^(^-^3^.^1^)=0.000794](https://tex.z-dn.net/?f=3.1%20%5BH%5E%2B%20%5D%3D%2010%5E%28%5E-%5E3%5E.%5E1%5E%29%3D0.000794)
</em>
<em>On dilution the concentration of a solution decreases and volume increases.</em>
<em>
</em>
<em>
</em>
<em>
</em>
<em>Volume of water to be added 
</em>
<em>
</em>
Answer:
ola what do u need to do?
