Answer:
See below
Explanation:
Q = m c T c = specific heat T = temp change Q = heat joules
32 = 4 c 40 <u> c = .2 J/g-C</u>
314 to 344 k is a change of 30 K
Q = m c T
= 4 * .2 * 30 = <u>24 Joules </u>
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Answer:
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Answer:
2621.75 j heat is required to increase the temperature 25.5°C to 46°C.
Explanation:
Given data:
Mass of sample = 142.1 g
Initial temperature = 25.5°C
Final temperature = 46°C
Specific heat capacity of Al = 0.90 J/g.°C
Solution:
Formula:
Q = m.c. ΔT
Q = amount of heat absorbed or released
m = mass of given substance
c = specific heat capacity of substance
ΔT = change in temperature
ΔT = 46°C - 25.5°C
ΔT = 20.5°C
Q = 142.1 × 0.90 J/g.°C × 20.5°C
Q = 2621.75 j
Thus, 2621.75 j heat is required to increase the temperature 25.5°C to 46°C.