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AysviL [449]
3 years ago
13

a section in a stained glass window is shaped like a trapezoid. the top base is 4 centimeters and the bottom base is 2.5 centime

ters long. if the area of the section is 3.9 square centimeters, how tall is the sectiona section in a stained glass window is shaped like a trapezoid. the top base is 4 centimeters and the bottom base is 2.5 centimeters long. if the area of the section is 3.9 square centimeters, how tall is the sectiona section in a stained glass window is shaped like a trapezoid. the top base is 4 centimeters and the bottom base is 2.5 centimeters long. if the area of the section is 3.9 square centimeters, how tall is the sectiona section in a stained glass window is shaped like a trapezoid. the top base is 4 centimeters and the bottom base is 2.5 centimeters long. if the area of the section is 3.9 square centimeters, how tall is the sectiona section in a stained glass window is shaped like a trapezoid. the top base is 4 centimeters and the bottom base is 2.5 centimeters long. if the area of the section is 3.9 square centimeters, how tall is the sectiona section in a stained glass window is shaped like a trapezoid. the top base is 4 centimeters and the bottom base is 2.5 centimeters long. if the area of the section is 3.9 square centimeters, how tall is the sectiona section in a stained glass window is shaped like a trapezoid. the top base is 4 centimeters and the bottom base is 2.5 centimeters long. if the area of the section is 3.9 square centimeters, how tall is the sectiona section in a stained glass window is shaped like a trapezoid. the top base is 4 centimeters and the bottom base is 2.5 centimeters long. if the area of the section is 3.9 square centimeters, how tall is the section
Chemistry
1 answer:
Sophie [7]3 years ago
6 0
I do not know honestly.
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Answer:

D. all of the above

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A bowl of trail mix and a bowl of soup are examples of what type of matter? 9 (a) solution (b) heterogeneous mixture (c) element
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The answer should be B.
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Read 2 more answers
10g of sugar is dissolved by water to make 200g of solution of sugar. What is the percent by mass of the solution?​
Scorpion4ik [409]

Explanation:

In sugar solution 200 g has sugar 10 g

In sugar solution 100 g has sugar 10/200 × 100

= 5 %w/w

7 0
3 years ago
Find percent yield:
saveliy_v [14]

<u>Answer:</u> The percent yield of the reaction is 91.8 %

<u>Explanation:</u>

To calculate the number of moles, we use the equation:

\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}     .....(1)

  • <u>For B_5H_9 :</u>

Given mass of B_5H_9 = 4.0 g

Molar mass of B_5H_9 = 63.12 g/mol

Putting values in equation 1, we get:

\text{Moles of }B_5H_9=\frac{4g}{63.12g/mol}=0.0634mol

  • <u>For oxygen gas:</u>

Given mass of oxygen gas = 10.0 g

Molar mass of oxygen gas = 32 g/mol

Putting values in equation 1, we get:

\text{Moles of oxygen gas}=\frac{10g}{32g/mol}=0.3125mol

The chemical equation for the reaction of B_5H_9 and oxygen gas follows:

2B_5H_9+12O_2\rightarrow 5B_2O_3+9H_2O

By Stoichiometry of the reaction:

12 moles of oxygen gas reacts with 2 moles of B_2H_5

So, 0.3125 moles of oxygen gas will react with = \frac{2}{12}\times 0.3125=0.052mol of B_2H_5

As, given amount of B_2H_5 is more than the required amount. So, it is considered as an excess reagent.

Thus, oxygen gas is considered as a limiting reagent because it limits the formation of product.

By Stoichiometry of the reaction:

12 moles of oxygen gas produces 5 moles of B_2O_3

So, 0.3125 moles of oxygen gas will produce = \frac{5}{12}\times 0.3125=0.130moles of water

Now, calculating the mass of B_2O_3 from equation 1, we get:

Molar mass of B_2O_3 = 69.93 g/mol

Moles of B_2O_3 = 0.130 moles

Putting values in equation 1, we get:

0.130mol=\frac{\text{Mass of }B_2O_3}{69.63g/mol}\\\\\text{Mass of }B_2O_3=(0.130mol\times 69.63g/mol)=9.052g

To calculate the percentage yield of B_2O_3, we use the equation:

\%\text{ yield}=\frac{\text{Experimental yield}}{\text{Theoretical yield}}\times 100

Experimental yield of B_2O_3 = 8.32 g

Theoretical yield of B_2O_3 = 9.052 g

Putting values in above equation, we get:

\%\text{ yield of }B_2O_3=\frac{8.32g}{9.052g}\times 100\\\\\% \text{yield of }B_2O_3=91.8\%

Hence, the percent yield of the reaction is 91.8 %

6 0
4 years ago
I NEED HELP FAST THIS IS DUE AT 9:00
aleksandrvk [35]
elements is the answer
4 0
3 years ago
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