Option B:
Both n and m must be rational.
Solution:
Given information:
Sum of two numbers, n and m are rational.
<u>To find which statements are true:</u>
Option A: Both n and m may be rational but do not have to be.
It is not true because n and m given is rational.
It have to be rational.
Option B: Both n and m must be rational.
Yes, n and m must be rational then only the sum of numbers are rational.
It is true.
Option C: Both n and m must be irrational.
Sum of irrationals will be sometimes irrational and sometimes can't add.
So it is not true.
Option D: One number is rational and the other is irrational.
Rational and irrational cannot be add.
So it is not true.
Option B is true.
Both n and m must be rational.
Yellow gumballs = 36
Total = 100

The probability of randomly selecting a yellow gumball is

Hope this helps.
well, is noteworthy that an x-intercept is when y = 0 or namely is a solution or root of the quadratic, so we know then that the x-intercepts or solutions are at (-1,0) and (3,0), that simply means that

![\bf -8=a(2)(-2)\implies -8=-4a\implies \cfrac{-8}{-4}=a\implies \boxed{2=a} \\\\[-0.35em] ~\dotfill\\\\ y=2(x+1)(x-3)\implies y=2(\stackrel{\mathbb{FOIL}}{x^2-2x-3})\implies y=2x^2-4x-6](https://tex.z-dn.net/?f=%5Cbf%20-8%3Da%282%29%28-2%29%5Cimplies%20-8%3D-4a%5Cimplies%20%5Ccfrac%7B-8%7D%7B-4%7D%3Da%5Cimplies%20%5Cboxed%7B2%3Da%7D%20%5C%5C%5C%5C%5B-0.35em%5D%20~%5Cdotfill%5C%5C%5C%5C%20y%3D2%28x%2B1%29%28x-3%29%5Cimplies%20y%3D2%28%5Cstackrel%7B%5Cmathbb%7BFOIL%7D%7D%7Bx%5E2-2x-3%7D%29%5Cimplies%20y%3D2x%5E2-4x-6)
Answer:
I provided a full answer and explaination in the picture attached. Good luck.