Consider the cross-sectional right triangle shown in the figure.
One of its sides is the height of the pyramid, with length H. The other side is half of the square base, so its length is 81 m. The hypotenuse of this triangle is the height of one of the faces.
By right triangle trigonometry,

,
thus,

.
Answer: C) 52 m
Answer:
Step-by-step explanation:
A = base *h /2
A = (4*15/2 )/2 = 15 in²
A = (1 and 3/7 *14/5 )/2 = (10/7 * 14/5 )/2 = 2 in²
A= (5 and 2/7 * 7/2) /2 = (37/7 * 7/2)/2 = 9.25 in²
9514 1404 393
Answer:
x = 60
y = 30
Step-by-step explanation:
Adjacent angles are supplementary.
(5x -180) +x = 180
6x = 360 . . . . . . . . . . add 180, collect terms
x = 60 . . . . . . . . divide by 6
Opposite angles are congruent.
2y = 60 . . . . . . 2y = x
y = 30 . . . . . . . .divide by 2
The value of x is 60; the value of y is 30.