Answer:
Because of statements (a), (c) and (d).
Explanation:
Let's evaluate each statement to know why they focus on higher alcohols instead of ethanol:
(a) It is easier to produce higher alcohols in microbes than it is to produce ethanol<u>.</u> This is true<u> since ethanol is the major biofuel in the world because it can be easily produced by fermentation technology developed a long time ago. Recently, higher alcohols are produced from microorganisms that are used as microbial cell factories.</u>
(b) Higher alcohols have a higher hygroscopicity than ethanol. This is false since ethanol is more hygroscopic than higher alcohols.
(c) Higher alcohols have a lower vapor pressure than ethanol. This is true, ethanol has a higher vapor pressure than higher alcohols. The vapor pressure is important since it can affect the proper cold starting of the engine.
(d) Higher alcohols have a higher energy density than ethanol. This is true since the production of higher alcohols as biofuels is more desirable than the ethanol because higher alcohols have a high energy density and other more advantages than the use of ethanol.
Therefore the answer of why did they focus on higher alcohols to add to or substitute gasoline instead of ethanol is because of the statements (a), (c) and (d).
I hope it helps you!
For this problem we can use 2 equations.
(1) - E = mC²
E = Energy of photon (J)
m = Mass of photon (kg) (1.67x10⁻²⁷ kg)
C = speed of light (3 x 10⁸ m/s)
(2) - E = hf
E = Energy of photon (J)
h = plank's constant (6.63 × 10⁻³⁴<span>J s)
f = frequency of the photon (Hz)
(1) = (2)
hence, </span>mC² = fh
by rearranging,
f = mC² / h
f = 1.67x10⁻²⁷ kg * (3 x 10⁸ m/s)² / (6.63 × 10⁻³⁴J s)
f = 2.27 x 10²³ Hz
= 6.022 × 1020
Explanation<em>;</em>
Mole of aluminium oxide (Al2O3) is
⇒ 2 x 27 + 3 x 16
Mole of aluminium oxide = 102 g
i.e., 102 g of Al2O3= 6.022 x 1023 molecules of Al2O3
Then, 0.051 g of Al2O3 contains = 6.022 x 1023 / (102 x 0.051 molecules)
= 3.011 x 1020 molecules of Al2O3
The number of aluminium ions (Al3+) present in one molecule of aluminium oxide is 2.
Therefore, the number of aluminium ions (Al3+) present in 3.11 × 1020 molecules (0.051g) of aluminium oxide (Al2O3)
= 2 × 3.011 × 1020
=<em> 6.022 × 1020</em>
<em>hope </em><em>it </em><em>helps</em><em>_</em>
