We have a right triangle with a 15m hypotenuse and a 8m leg. If we use x for the missing leg then the Pythagorean Theorem states that:

Then we have to solve that equation for x:
![\begin{gathered} x^2=15^2-8^2=225-64 \\ x^2=161 \\ x=\sqrt[]{161} \end{gathered}](https://tex.z-dn.net/?f=%5Cbegin%7Bgathered%7D%20x%5E2%3D15%5E2-8%5E2%3D225-64%20%5C%5C%20x%5E2%3D161%20%5C%5C%20x%3D%5Csqrt%5B%5D%7B161%7D%20%5Cend%7Bgathered%7D)
So the answer is the square root of 161.
<span>-2x-3=y in standard form
=
2x + y = -3
hope it helps</span>
Multiply both sides by 2
(2) 18 = x/2 (2)
the /2 (2) gets canceled out
so it's 36= x
Hope this helps
Its 3l-40 or 5l-3 the answer is