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Alexus [3.1K]
2 years ago
5

Which of the following quotients are negative check all that apply

Mathematics
1 answer:
ella [17]2 years ago
4 0
With the true and the right negative
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F ind the volume under the paraboloid z=9(x2+y2) above the triangle on xy-plane enclosed by the lines x=0, y=2, y=x
olga nikolaevna [1]

Answer:

The answer is 48 units³

Step-by-step explanation:

If we simply draw out the region on the x-y plane enclosed between these lines we realize that,if we evaluate the integral the limits all in all cannot be constants since one side of the triangular region is slanted whose equation is given by y=x. So the one of the limit of one of the integrals in the double integral we need to evaluate must be a variable. We choose x part of the integral to have a variable limit, we could well have chosen y's limits as non constant, but it wouldn't make any difference. So the double integral we need to evaluate is given by,

V=\int\limits^2_0 {} \, \int\limits^{x=y}_0 {z} \, dx dy\\V=\int\limits^2_0 {} \, \int\limits^{x=y}_0 {9(x^{2}+y^{2})} \, dx dy

Please note that the order of integration is very important here.We cannot evaluate an integral with variable limit last, we have to evaluate it first.after performing the elementary x integral we get,

V=9\int\limits^2_0 {4y^{3}/3} \, dy

After performing the elementary y integral we obtain the desired volume as below,

V= 48 units^{3}

4 0
3 years ago
17.25 round up to ones
Irina18 [472]
17.24

Since 7 comes after 5 we need to round to the next number.....18.00

17.24 rounded to ones = 18.00

Hope I helped:P

7 0
3 years ago
Read 2 more answers
Can you please help me solve this answer plz
Scilla [17]
Do the 15 new people fill the gondola?

5 0
3 years ago
If the area of square 3 is 80 cm² and thee area of square 2 is 100 cm², what is the area of square 1?
swat32

Answer:

260 cm²

Step-by-step explanation:

Please see the attached picture for the full solution.

5 0
2 years ago
Everyone needs to get off of social and help us -_-
JulsSmile [24]
(x+2)(x+8)(x+k)=x^3+9x^2+6x-16

(x^2+10x+16)(x+k)=x^3+9x^2+6x-16

x^3+10x^2+16x+kx^2+10kx+16k=x^3+9x^2+6x-16

kx^2+10kx+16k=-x^2-10x-16

k(x^2+10x+16)=-x^2-10x-16

k=(-x^2-10x-16)/(x^2+10x+16)

k=-1

so the width is (x-1)




7 0
3 years ago
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