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bazaltina [42]
3 years ago
10

A metallic spherical ball of radius 14 cm is being melted and recast it into spherical balls of radius 2 cm. How many spherical

balls will be created? Round your answer to the nearest whole number.
Mathematics
1 answer:
mojhsa [17]3 years ago
4 0

Volume of sphere = 4/3 x pi x r^3

Volume of large sphere:

4/3 x 3.14 x 14^3 = 11488.21 cubic cm

Volume of smaller sphere:

4/3 x 3.14 x 2^3 = 33.49 cubic cm

Number of small spheres = volume of large sphere/ volume of small sphere

11488.21 / 33.49 = 343.03

Round to 343 small spheres

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Solve 1/3x - 5/6x =1/4
Harrizon [31]

Answer:

-1/2

Step-by-step explanation:

Given:

\frac{1}{3}x  - \frac{5}{6} x = \frac{1}{4}

Find the common denominator for the fractions, which is 6. Rewrite 1/3 as 2/6.

\frac{2}{6}x  - \frac{5}{6} x = \frac{1}{4}

Combine like terms.

-\frac{3}{6} x = \frac{1}{4}

Simplify.

-0.5x = 1/4

Divide both sides by -0.5.

x = -1/2 = -0.5

Please mark as Brainliest! :)

8 0
3 years ago
WILL MAEK BRAINLIST <br>A shop has 20 pens. 12 of them are red. What percent of them are red?<br>​
dlinn [17]

Answer:

12/20×100percent

=12×5percent

=60percent answer

4 0
2 years ago
Pls help, I will give brainlist!
LenKa [72]

Answer:

Step-by-step explanation:

2.)A=\frac{bh}{2}

\frac{15*10}{2}=75.

3.) years to month

6 years is 72 month+2 month=74 month

month to days

74 month=2250.84days.

6 0
3 years ago
Two sets of data are shown.
dezoksy [38]

Answer:less than.

Step-by-step explanation: it less than something.

4 0
3 years ago
2. A square-based tent has the cross-sectional
ollegr [7]

(a) Length of the height is 2.732 m

(b) Length of the base is 5.466 m

<u>Explanation:</u>

An image is attached for reference.

(a)

In ΔAOB,

sin 30^o = \frac{AO}{AB} \\\\0.5 = \frac{AO}{2} \\\\AO = 1 m

In ΔBGD,

sin 60^o = \frac{BG}{BD} \\\\0.866 = \frac{BG}{2} \\\\BG = 1.732 m

According to the figure, BG = OE = 1.732 m

Height of the tent, AE = AO + OE

                                  = 1 m + 1.732 m

                                  = 2.732 m

(b)

DF = ?

In ΔAOB,

tan 30^o = \frac{AO}{OB} \\\\0.577 = \frac{1}{OB} \\\\OB = 1.733 m\\\\\\

According to the figure, OB = GE = 1.733 m

In ΔBGD,

tan 60^o = \frac{BG}{DG} \\\\1.732 = \frac{1.732}{DG}\\ \\DG = 1m

According to the figure, DE = DG + GE

                                      DE = 1 m + 1.733 m

                                     DE = 2.733 m

Length of the base, DF = 2 X DE

                              DF = 2 X 2.733 m

                               DF = 5.466 m

8 0
3 years ago
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