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vivado [14]
3 years ago
14

What is the average isotopic mass of an element that has the following abundances in nature? Isotopic mass: X20 X22 X23 Abundanc

es in natures: 90.5 % 8.0 % 1.5 %
Chemistry
1 answer:
Paladinen [302]3 years ago
8 0

Answer: 20.2

Explanation:

Mass of isotope 1 = 20

% abundance of isotope 1 = 90.5% = \frac{90.5}{100}=0.905

Mass of isotope 2 = 22

% abundance of isotope 2 = 8.0% = \frac{8}{100}=0.08

Mass of isotope 3 = 23

% abundance of isotope 3 = 1.5% = \frac{1.5}{100}=0.015

Formula used for average atomic mass of an element :

\text{ Average atomic mass of an element}=\sum(\text{atomic mass of an isotopes}\times {{\text { fractional abundance}})

A=\sum[(20\times 0.905+(22\times 0.08)+(23\times 0.015]

A=20.2

Therefore, the average atomic mass of the element is 20.2.

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Which pair of atoms has the highest electronegativity difference? <br> ca, f, h, p, na
mamaluj [8]
I will state the electronegativities of each element.
Ca = 1.00
F = 3.98
H = 2.20
P = 2.19
Na = 0.93
The highest electronegative element is F (Fluorine).
6 0
3 years ago
2. Will calcite scratch feldspar? Why or why not?
ahrayia [7]

Answer: No

Explanation: The reason for this is because calcite has a hardness of 9 while feldspar has a hardness of 21. Calcite can scratch Gypsum which has  a hardness of 3.

7 0
4 years ago
Assuming an efficiency of 30.80%, calculate the actual yield of magnesium nitrate formed from 147.4g of magnesium and excess cop
Reil [10]

Answer:

The answer to your question is 280 g of Mg(NO₃)₂

Explanation:

Data

Efficiency = 30.80 %

Mg(NO₃)₂ = ?

Magnesium = 147.4 g

Copper (II) nitrate = excess

Balanced Reaction

                     Mg  +   Cu(NO₃)₂    ⇒    Mg(NO₃)₂   +   Cu

                  Reactants           Elements            Products

                         1                          Mg                     1

                         1                          Cu                      1

                         2                          N                       2

                         6                          O                       6

Process

1.- Calculate the theoretical yield

Molecular weight Mg = 24

Molecular weight Mg(NO₃)₂ = 24 + (14 x 2) + (16 x 6)

                                              = 24 + 28 + 96

                                              = 148 g

                           24 g of Mg  --------------------  148 g of Mg(NO₃)₂

                          147.4 g of Mg -------------------   x

                            x = (147.4 x 148) / 24

                            x = 908.96 g of Mg(NO₃)₂

2.- Calculate the Actual yield

yield percent = \frac{actual yield}{theoretical yield}

Solve for actual yield

Actual yield = Yield percent x Theoretical yield

Substitution

Actual yield = \frac{30.8}{100} x 908.96

Actual yield = 279.95 ≈ 280g

                     

4 0
3 years ago
What compound requires the most energy to melt
FinnZ [79.3K]

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7 0
3 years ago
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Explanation:

one mole of any substance there are 6.022×1023 units of that substance. (This number is called Avogadro's number, NA.)

We need to convert the mass of silicon to moles using the molar mass of silicon, 28.06gmol. This number means that one mole of pure silicon would have a mass of 28.06g. Our given mass, however, is in milligrams; to convert this to grams we'll use the conversion factor 1g103mg:

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Now, using silicon's molar mass, we'll convert this mass to moles of Si:

0.00586g Si(1mol Si28.06g Si)=2.09×10−4mol Si

Finally, let's use Avogadro's number to convert

6 0
3 years ago
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