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Afina-wow [57]
3 years ago
9

What does the subscript 2 indicate in the formula O2? Oxygen transferred 2 electrons to form the bond. Each oxygen atom is shari

ng two electrons. There are two atoms in the molecule. There are two valence electrons in the molecule.
Chemistry
2 answers:
xxMikexx [17]3 years ago
5 0

Answer:

C) There are two atoms in the molecule.

Explanation:

In convention (accepted style) of writing out chemical equations and formular, it is understood that the subscript after an element tells us the number of atoms of said element.

For example, in the compound below, we can tell that;

H₂CO₃

There are 2 hydrogen atoms, 1 carbon atom and 3 Oxygen atoms.

We apply same principle to O2 and we now know the number 2 signifies the number of atoms present in the molecule.

Applying elimination on the other options, we have;

A) This option is not correct because electrons transferred or gained are represented by a charge which is the superscript after the element. E.g O²⁻

B) This option is wrong because sharing of electrons are not represented in the formular of a molecule or compound.

D) Valance electrons are usually represented by oxidation number. So this is wrong too.

Tom [10]3 years ago
3 0

Answer:There are two atoms in the molecule.

Explanation: All gases are diatomic i.e they are covalently bonded to another atom of the same element in order to attain stability. O atom is usually unstable because of it's incompletely filled outermost shell.

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What is the empirical formula for a compound that is 43.6% phosphorus
Kazeer [188]

Answer:

d.   P2O5.

Explanation:

We find the ratio of the atoms by dividing the percentages by the relative atomic masses:

P :  43.6 / 30.974 = 1.4076

O:  56.4 / 15.999 =  3.5252

1.4076 : 3.5252

= 1 : 2.5

= 2:5.

So the answer is P2O5.

3 0
3 years ago
A buffer contains 0.18 mol of propionic acid (C2H5COOH) and 0.26 mol of sodium propionate (C2H5COONa) in 1.20 L. What is the pH
Yuki888 [10]

Answer:

1) pH = 5.05

2) pH = 5.13

3) pH = 4.97

Explanation:

Step 1: Data given

Number of moles of propionic acid = 0.18 moles

Number of moles sodium propionate = 0.26 moles

Volume = 1.20 L

Ka = 1.3 * 10^-5    → pKa = 4.989

Step 2: Calculate concentrations

Concentration = moles / volume

[acid]= 0.18/ 1.2 =0.150 M

[salt]= 0.26/ 1.3 = 0.217 M

pH = 4.89 + log(0.217/0.150)=<u>5.05</u>

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What is the pH of the buffer after the addition of 0.02 mol of NaOH?

moles acid = 0.18 - 0.02 = 0.16

[acid]= 0.16/ 1.2=0.133 M

moles salt = 0.26 + 0.02 = 0.28

[salt]= 0.28/ 12=0.233

pH = 4.89 + log 0.233/ 0.133 = 5.13

What is the pH of the buffer after the addition of 0.02 mol of HI?

moles acid = 0.18+ 0.02 = 0.20 moles

[acid]= 0.20/ 1.2 = 0.167 M

[salt]= 0.26 - 0.02= 0.24 moles

[salt]= 0.24/ 1.2 = 0.20 M

pH = 4.89 + log 0.20/ 0.167= 4.97

8 0
3 years ago
4 Nitrogen monoxide reacts with oxygen like this:
olga2289 [7]

a. mol O₂=0.5

b. volume O₂ = 25 cm³

c. i. the total volume of the two reactants = 75 cm³

c. ii. the volume of nitrogen dioxide formed = 50 cm³

<h3>Further explanation</h3>

Reaction

2NO(gas) + O₂(gas) ⇒ 2NO₂ (gas)

a.

mol NO = 1

From the equation, mol ratio NO : O₂ = 2 : 1, so mol O₂ :

\tt \dfrac{1}{2}\times 1=0.5

b.

From Avogadro's hypothesis, at the same temperature and pressure, the ratio of gas volume will be equal to the ratio of gas moles  

Because mol ratio NO : O₂ = 2 : 1, so volume O₂ :

\tt \dfrac{1}{2}\times 50~cm^3=25~cm^3

c.

i. total volume of reactants : 25 cm³+ 50 cm³=75 cm³

ii. the volume of nitrogen dioxide formed :

mol ratio NO : NO₂ = 2 : 2, so volume NO₂ = volume NO = 50 cm³

6 0
3 years ago
Calculate the number of ATOMS in 1.0 mole of O2.
Wewaii [24]
There is 6.02*10^23 molecule per mole. And there is 2 atoms per oxygen molecule. So the answer is 1.204*10^24 atoms in 1.0 mole of O2.
7 0
3 years ago
Read 2 more answers
Describe an experiment to show that water contains hydrogen and oxygen only​
kondaur [170]

Answer:

Electrolysis

Explanation:

The electrolysis of water is one such experiment that shows that water is made up of hydrogen and oxygen atoms only in the ratio of 2 to 1.

In the electrolysis of water, electricity is passed through acidified water to cause it to decompose.

The electrolysis of water is also known as the electrolysis of dilute tetraoxosulphate  (VI) acid.

At the cathode, H⁺ ions are discharged and hydrogen gas is liberated:

               2H⁺       +     2e⁻     →        H₂

At the anode, both the sulfate ion and hydroxyl ions migrate to this electrode. Only the OH⁻ is selected for preferential discharge due to its lower position in that activity series.

         4OH⁻  →   2H₂O    +    O₂     +     4e⁻

Oxygen gas is produced at the anode.

This electrolysis demonstrates the volumetric composition of water that is, 2 volumes of hydrogen at the cathode and 1 volume of oxygen at the anode.

5 0
3 years ago
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