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Afina-wow [57]
3 years ago
9

What does the subscript 2 indicate in the formula O2? Oxygen transferred 2 electrons to form the bond. Each oxygen atom is shari

ng two electrons. There are two atoms in the molecule. There are two valence electrons in the molecule.
Chemistry
2 answers:
xxMikexx [17]3 years ago
5 0

Answer:

C) There are two atoms in the molecule.

Explanation:

In convention (accepted style) of writing out chemical equations and formular, it is understood that the subscript after an element tells us the number of atoms of said element.

For example, in the compound below, we can tell that;

H₂CO₃

There are 2 hydrogen atoms, 1 carbon atom and 3 Oxygen atoms.

We apply same principle to O2 and we now know the number 2 signifies the number of atoms present in the molecule.

Applying elimination on the other options, we have;

A) This option is not correct because electrons transferred or gained are represented by a charge which is the superscript after the element. E.g O²⁻

B) This option is wrong because sharing of electrons are not represented in the formular of a molecule or compound.

D) Valance electrons are usually represented by oxidation number. So this is wrong too.

Tom [10]3 years ago
3 0

Answer:There are two atoms in the molecule.

Explanation: All gases are diatomic i.e they are covalently bonded to another atom of the same element in order to attain stability. O atom is usually unstable because of it's incompletely filled outermost shell.

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Which is not a descriptor or tactic used by abusers?
attashe74 [19]
It should be B. All of the other choices are used often by abusers
4 0
3 years ago
Be<br><br> Name the element.<br><br> Number of shells?<br><br> Valence electrons?
Vedmedyk [2.9K]

Answer:

Name the element: Beryllium

Number of shells:  4

Valence electrons: 2

Explanation:

4 0
3 years ago
A sample of element X contains 90% X-35 atoms, 8.0% X-37 atoms, and 2.0% X-38 atoms. The average atomic mass will be closest to
Ne4ueva [31]

To find average atomic mass you multiply the mass of each isotope by its percentage, and then add the values up.

35 * 0.90 + 37 * 0.08 + 38 * 0.02 = 35.22

Average atomic mass closest to 35.22 amu.

6 0
3 years ago
Read 2 more answers
When a 12.8 g sample of KCL dissolves in 75.0 g of water in a calorimeter the temp. drops from 31 Celsius to 21.6 Celsius. Calcu
Delicious77 [7]

Answer:

Step 1: Calculate qsur (the surrounding is

usually the water)

qsur = ? J

m = 75.0 g water

c = 4.184 J/g

oC

ΔT = (Tfinal- Tinitial)= (21.6 – 31.0) = -9.4 oC

qsur = m · c · (ΔT)

qsur = (75.0g) (4.184 J/g

oC) (-9.4 oC)

qsur = - 2949.72 J

First, using the information we know that we

must solve for qsur, which is the water. We know

the mass for water, 75.0g, the specific heat of

the water, 4.184 j/g

o

c, and the change in

temperature, 21.6-31.0 = -9.4 oC. Plugging it

into the equation, we solve for qsur.

Step 2: Calculate qsys qsys = - (qsur)

qsys = - (- 2949.72 J)

qsys = + 2949.72

In this case, the qsur is negative, which means

that the water lost energy. Where did it go? It

went to the system. Thus, the energy of the

system is negative, opposite, the energy of the

surrounding.

Step 3: Calculate moles of the substance

that is the system

Given: 12.8 g KCl

Mol system = (g system given)

(molar mass of system)

Mol system = (12.8 g KCl)

(39.10g + 35.45g)

Mol system = 12.8 g KCl

74.55 g

Mol system = 0.172

Here, we solve for the mol in the system by

using the molar mass of the material in the

system.

Step 4: Calculate ΔH ΔH = q sys .

Mol system

ΔH= + 2949.72 J

0.172 mol

ΔH= +17179.81 J/mol or +1.72 x 104

J/mol

i hope this helps

7 0
3 years ago
Determine the number of significant figures in the measurement quantity: 2600. kg.
xxMikexx [17]

Answer:

2600 kg has 4 significant figures

Explanation:

Any different number to zero is a significant figure

For example, 1.8 → 2 significant figures

When you  have 0 in the middle of two numbers, we consider it as a significant number

For example, 3.02 → 3 significant figures

When you have 0 on the left in the measure, we do not consider as a sgnificant figures

For example 0.0010 → 2 significant figures (10)

3.0 → 2 significant figures (0 is on the right, not the left)

7 0
2 years ago
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