What does the subscript 2 indicate in the formula O2? Oxygen transferred 2 electrons to form the bond. Each oxygen atom is shari
2 answers:
You might be interested in
Explanation:
When carbon atom tends to form single bonds then its hybridization is , when carbon atom tends to form double bond then its hybridization is
and when a carbon atom is attached to a triple bond or with two double bonds then its hydridization is sp.
For example, in HCN molecule there is a triple existing between the carbon and nitrogen atom.
So, hybridization of carbon in this molecules is sp. Moreover, nitrogen atom is also attached via triple bond and it also has a lone pair of electrons. Hence, the hybridization of nitrogen atom is also sp.
Thus, we can conclude that s and p type of orbitals overlap to form the sigma bond between C and N in H−C≡N:
<u>Answer:</u> The amount of heat produced by the reaction is -21.36 kJ
<u>Explanation:</u>
Enthalpy change is defined as the difference in enthalpies of all the product and the reactants each multiplied with their respective number of moles.
The equation used to calculate enthalpy change is of a reaction is:
For the given chemical reaction:
The equation for the enthalpy change of the above reaction is:
We are given:
Putting values in above equation, we get:
To calculate the number of moles, we use ideal gas equation, which is:
where,
P = pressure of the gas = 1.00 bar
V = Volume of the gas = 2.67 L
n = number of moles of gas = ?
R = Gas constant =
T = temperature of the mixture =
Putting values in above equation, we get:
To calculate the heat released of the reaction, we use the equation:
where,
q = amount of heat released = ?
n = number of moles = 0.108 moles
= enthalpy change of the reaction = -197.8 kJ/mol
Putting values in above equation, we get:
Hence, the amount of heat produced by the reaction is -21.36 kJ
I'm assuming that by "miles" you mean moles.
If O2 is the excess reactant, that means Fe is the limiting reactant. That means that the amount of product being formed depends on the amount of Fe reactant present. To calculate the moles of Fe2O3 formed, start with the given 6.4 moles of Fe and use the mole to mole ratio given by the reaction as shown below:
6.4 mol Fe x
= 3.2 mol Fe2O3
If O2 is the excess reactant, that means Fe is the limiting reactant. That means that the amount of product being formed depends on the amount of Fe reactant present. To calculate the moles of Fe2O3 formed, start with the given 6.4 moles of Fe and use the mole to mole ratio given by the reaction as shown below:
6.4 mol Fe x