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3 years ago

What can you infer about the volume of an object imagined with a greater mass?

1 answer:

3 0

We tend to think the greater the mass, the greater the volume but that is not true. What weighs more a pound of lead or a pound of feathers? Obviously they are the same however there would be a lot more feathers than lead. Mass and volume are not really related.

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A hypothesis is based on the analysis of data collected in a controlled

kiruha [24]

True? I really don’t know but ones someone

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3 years ago

Read 2 more answers

(a) 7.56 0.375 +14.3103

Musya8 [376]

Answer:Use the Law of Sines to solve the triangle ABC if it exists: a) A= 68.41°, B = 54.23”, a = 12.75 ft. b = b = b = a sub ź111347.

Explanation:

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2 years ago

Describe the three temperature scales used in the laboratory and in everyday life: the Fahrenheit, Celsius, and Kelvin scales.

yuradex [85]

Explanation:

Fahrenheit Scale

Fahrenheit temperature scale is the scale which is based on:

(a) For freezing point of the water, 32 °F.

(b) For boiling point of the water, 212 °F.

With interval between two being divided into equal 180 parts.

Celsius Scale

Celsius temperature scale is the scale which is based on:

(a) For freezing point of the water, 0 °C

(b) For boiling point of the water, 100 °C.

With interval between two being divided into equal 100 parts.

Kelvin Scale 

It denotes the triple point of water where the solid, liquid, and gas phases exist in equilibrium which is at 273.16 K.

kelvin is defined as 1/ 273.16 of triple point temperature.

6 0

3 years ago

In a particular experiment, 2.50-g samples of each reagent are reacted. The theoretical yield of lithium nitride is ________ g.

Neporo4naja [7]

Answer:

4.18 g

Explanation:

The formula for the calculation of moles is shown below:

$moles = \frac{Mass\ taken}{Molar\ mass}$

Given: For Li

Given mass = 2.50 g

Molar mass of Li = 6.94 g/mol

Moles of Li = 2.50 g / 6.94 g/mol = 0.3602 moles

Given: For $N_2$

Given mass = 2.50 g

Molar mass of $N_2$ = 28.02 g/mol

Moles of $N_2$ = 2.50 g / 28.02 g/mol = 0.08924 moles

According to the given reaction:

$6Li+N_2\rightarrow 2Li_3N$

6 moles of Li react with 1 mole of $N_2$

1 mole of Li react with 1/6 mole of $N_2$

0.3602 mole of Li react with $\frac {1}{6}\times 0.3602$ mole of $N_2$

Moles of $N_2$ that will react = 0.06 moles

Available moles of $N_2$ = 0.08924 moles

$N_2$ is in large excess. (0.08924 > 0.06)

Limiting reagent is the one which is present in small amount. Thus,

Li is limiting reagent.

The formation of the product is governed by the limiting reagent. So,

6 moles of Li gives 2 mole of $Li_3N$

1 mole of Li gives 2/6 mole of $Li_3N$

0.3602 mole of Li react with $\frac {2}{6}\times 0.3602$ mole of $Li_3N$

Moles of $Li_3N$ = 0.12

Molar mass of $Li_3N$ = 34.83 g/mol

Mass of $Li_3N$ = Moles × Molar mass = 0.12 × 34.83 g = 4.18 g

Theoretical yield = 4.18 g

5 0

3 years ago

What is the lowest temperature that a substance can reach?

kobusy [5.1K]

Absolute zero that means cooling - 0 degree

3 0

3 years ago