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AnnZ [28]
2 years ago
6

Which forces of attraction do you think are stronger, the attractions that are broken or the new attractions that are formed? Ex

plain your reasoning. *
Chemistry
1 answer:
jasenka [17]2 years ago
8 0

Answer: The forces of attraction are stronger in new attractions that are formed.

Explanation:

When a chemical reaction takes place between two or more different compounds then less reactive substance is displaced by the more reactive substance.

During this process, when bonds are broken between the reactants then it means the force of attraction is less stronger. The formation of new compounds occur because force of attraction is more in these new substances due to which its atoms come closer to each other.

Thus, we can conclude that forces of attraction are stronger in new attractions that are formed.

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Mass of 2×10^21 number of atoms of an element is 0.4g. What is the mass of 0.5 mole of the element?
alexandr402 [8]

Answer:

66.7 g

Explanation:

Number of atoms = 2×10²¹

Mass of 2×10²¹ atoms = 0.4 g

Mass of 0.5 moles of that element = ?

Solution:

1 mole contain 6.022×10²³ atoms

2×10²¹ atoms × 1 mol / 6.022×10²³ atoms

0.33×10⁻² mol

0.003 mol

 0.003 mole have mass of 0.4 g

0.5 mol have mass 0.5/0.003×0.4 g = 66.7 g

5 0
2 years ago
bartleby whihch of the foololwing is the correct cell notation for the reaction Hg2 Cd(s)-> Cd2 2Hg(l)
Misha Larkins [42]

Cd2+ + 2Hg Cd + Hg22+. Both Cd2+ + 2e Cd(s) -0.40 and Hg22+ + 2e 2Hg(l) 0.79

A chemical reaction known as an oxidation-reduction (redox) reaction includes the exchange of electrons between two substances.

Any chemical reaction in which the oxidation number of a molecule, atom, or ion changes by acquiring or losing an electron is referred to as an oxidation-reduction reaction. Decomposition Reaction is one of the several redox reactions.

This is the redox reaction's overall cell potential. Cd2+ + 2Hg Cd + Hg22+. Both Cd2+ + 2e Cd(s) -0.40 and Hg22+ + 2e 2Hg(l) 0.79

Reduction describes the increase in electrons. Oxidation and reduction always occur jointly because any loss of electrons by one substance must be followed by a gain of electrons by another.

Therefore, oxidation-reduction processes or simply redox reactions are other names for electron-transfer events.

Learn more about redox reactions here brainly.com/question/8727728.

#SPJ4.

3 0
1 year ago
A 15.0-L scuba diving tank contains a helium-oxygen (heliox) mixture made up of 23.0 g of He and 4.14 g of O2 at 298 K. Calculat
EleoNora [17]

<u>Answer:</u> The mole fraction of Helium is 0.978 and that of oxygen gas is 0.022

<u>Explanation:</u>

To calculate the number of moles, we use the equation:

\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}      .....(1)

  • <u>For helium:</u>

Given mass of helium = 23 g

Molar mass of helium = 4 g/mol

Putting values in equation 1, we get:

\text{Moles of helium}=\frac{23g}{4g/mol}=5.75mol

  • <u>For oxygen gas:</u>

Given mass of oxygen gas = 4.14 g

Molar mass of oxygen gas = 32 g/mol

Putting values in equation 1, we get:

\text{Moles of oxygen gas}=\frac{4.14g}{32g/mol}=0.129mol

Mole fraction of a substance is given by:

\chi_A=\frac{n_A}{n_A+n_B}

  • <u>For helium:</u>

Moles of helium = 5.75 moles

Total moles = [5.75 + 0.129] = 5.879 moles

Putting values in above equation, we get:

\chi_{(He)}=\frac{5.75}{5.879}=0.978

  • <u>For oxygen gas:</u>

Moles of oxygen gas = 0.129 moles

Total moles = [5.75 + 0.129] = 5.879 moles

Putting values in above equation, we get:

\chi_{(O_2)}=\frac{0.129}{5.879}=0.022

Hence, the mole fraction of Helium is 0.978 and that of oxygen gas is 0.022

3 0
3 years ago
Please help !!<br><br> Science question
Lelu [443]
The answer is 2Eu + 3H2O —> Eu2O3+3H2.
Or in other words, change the first one to 3 and the second to 3 as well.
3 0
3 years ago
ASAP I AM GIVING BRAINLIEST PLEASEEEEEEEEE HELPPPPPPPPPPPPPPPPPP
zepelin [54]

Answer:

B?

Explanation:

In the example, the amount of hydrogen is 202,650 x 0.025 / 293.15 x 8.314472 = 2.078 moles. Use the mass of the hydrogen gas to calculate the gas moles directly; divide the hydrogen weight by its molar mass of 2 g/mole. For example, 250 grams (g) of the hydrogen gas corresponds to 250 g / 2 g/mole = 125 moles.

7 0
3 years ago
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