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olga2289 [7]
3 years ago
9

Find the distance between the points given (0, -6) and (9,6)

Mathematics
2 answers:
MrRissso [65]3 years ago
7 0
The first one is less than the second one
Oduvanchick [21]3 years ago
3 0

Answer:

(9,12)

Step-by-step explanation:

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What is the mean absolute deviation of the data: 10, 20, 15, 17, and 13?
Rufina [12.5K]

Answer:

2.8

Step-by-step explanation:

1) find the mean of the data set. = 15

2) find the abs value of the diff between each data value and the mean: |data value – mean|.

|10-15|=5, |20-15|=5, |15-15|=0, |17-15|=2, |13-15|=2

3) find the sum of the abs values of the diff = 14

4) divide the sum of the abs value by the number of data values = 14/5 = 2.8

5 0
3 years ago
How many times does 7 go into 2,400
aksik [14]

Answer:

about 324 times.

Step-by-step explanation:

2400/7

342.857142857

4 0
3 years ago
Read 2 more answers
Use decimals to spray is 0.719 in expanded form
miss Akunina [59]
The answer would be 0.+0.7+0.01+0.009 hope it helps
6 0
3 years ago
The drama club is selling tickets to the play to raise money for the shows expenses. Each student ticket sales for five dollars
djyliett [7]

Answer:

45 student tickets and 30 adult tickets

Step-by-step explanation:

You can check your work by plugging both answers into both of the original equations. :)

8 0
3 years ago
If p = .8 and n = 50, then we can conclude that the sampling distribution of pˆ is approximately a normal distribution
FrozenT [24]

Answer:

Yes we can conclude.

Step-by-step explanation:

The sampling distribution of \hat{p} can be approximated as a Normal Distribution only if:

np and nq are both equal to or greater than 10. i.e.

  • np ≥ 10
  • nq ≥ 10

Both of these conditions must be met in order to approximate the sampling distribution of \hat{p} as Normal Distribution.

From the given data:

n = 50

p = 0.80

q = 1 - p = 1 - 0.80 = 0.20

np = 50(0.80) = 40

nq = 50(0.20) = 10

This  means the conditions that np and nq must be equal to or greater than 10 is being satisfied. So, we can conclude that the sampling distribution of pˆ is approximately a normal distribution

6 0
3 years ago
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