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DENIUS [597]
3 years ago
11

One risk associated with modern computing is _____.

Computers and Technology
1 answer:
almond37 [142]3 years ago
5 0

Answer:

I think that one risk associated with modern computing is "hardware and software failure"

Explanation:

Hardware and software failure - such as power loss or data corruption .

Some other risks are also there like-Malware - malicious software designed to disrupt computer operation,viruses - computer code that can copy itself and spread from one computer to another, often disrupting computer operations.

THANKYOU

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Vitamins and minerals dissolve easily in water.True or false?
noname [10]
True vitamins and minerals dissolves in water
8 0
3 years ago
Pls help me pls I’m struggling
evablogger [386]

Answer:Turn Right () Degrees (block)

The turn right () degrees block is a Motion block and a stack block. The block turns its sprite's direction the specified amount of degrees clockwise.

6 0
3 years ago
Write a c++ application that computes gross salary for Mr.A,given that during the interview session and before started work, it
Vesnalui [34]

Answer:

# include <iostream>

using namespace::std;

int main()

{   int hrs;

float hrly_rate= 47;

double net_Sl;

float t1;

float t2;

float t3;

float t4;

float t5;

double grss_Pay;

float bons;

   cout<<"Enter number of hours worked";

   cin>>hrs;

   net_Sl= 47 * 387;

       t1 = (4.7 * net_Sl)/100;

       t2= 87;

       t3=(3.7 * net_Sl)/100;

       t4=3;

       t5=(0.47 * net_Sl)/100;

       grss_Pay= net_Sl- t1 - t2 -t3 - t4 - t5;

       float tmp=grss_Pay;                  

       double in_hnd;

       if (grss_Pay<10)

       {

           bons= (5 * grss_Pay)/100;

           in_hnd=grss_Pay+bons;

           grss_Pay=grss_Pay-grss_Pay;

       }

       else if (grss_Pay>10 ||grss_Pay<500)

       { bons= (10 * grss_Pay)/100;

         tmp=grss_Pay-grss_Pay;

         in_hnd=in_hnd+bons;

       }

       else if (grss_Pay>500|| grss_Pay<1000)

       { bons= 500;

         grss_Pay=grss_Pay-grss_Pay;

         in_hnd=in_hnd+bons;

       }

       else if (grss_Pay>1000 || grss_Pay<=2000)

       { bons= 600;

         grss_Pay=grss_Pay-grss_Pay;

         in_hnd=in_hnd+bons;

       }

       else if (grss_Pay>2000)

       { bons= (5 * grss_Pay)/100;

         grss_Pay=grss_Pay-grss_Pay;

         in_hnd=in_hnd+bons;

       }

        cout<<"Final Salary"<<in_hnd;

        return 0;

}

Explanation:

Please check the answer section.

4 0
3 years ago
A security operation center (SOC) analyst investigates the propagation of a memory-resident virus across the network and notices
masya89 [10]

A type of virus that influences this circumstance in the network bandwidth is a worm.

<h3>What is Virus in technology?</h3>

In computers and technology, viruses may be characterized as a sort of malicious software, or malware, that extends between computers and provokes a deterioration of data and software either partially or completely.

The complete question is as follows:

  • A micro virus
  • a multipartite virus
  • A worm
  • a program virus.

Worms are memory-resident viruses that duplicate over the network resources. The primary consequence of this type of virus is to rapidly eradicate network bandwidth with its duplication.

This virus may also be competent to accomplish a Denial of services invasion by slamming O.S and servers.

Therefore, the correct option for this question is C, i.e. a worm.

To learn more about Computer viruses, refer to the link:

brainly.com/question/26128220

#SPJ1

5 0
2 years ago
(Java) I need help understanding what to code for these methods.
Nuetrik [128]

Answer:

public Mysring(char[] Original)

{

        int size= Original.length();

       for(int i=0;i<=size;i++)

       {

           arr[i]=Original[i];

       }

}

Public Mystring(String Original)

{

  char[] arr=String.toCharArray();

}

Public Mystring(Mystring Original)

{

   Int len=Original.arr.length();

   for(int i=0;i<=len;i++)

   {

        arr[i]=Orginal.arr[i];

   }

}

public int length()

{

    Int len=arr.length();

   return len;

}

Public char charAt(int index)

{

     try

     {

      System.out.println(arr[index]);

     }

     catch(IndexOutOfBoundsException ex)

     {

          throw ex;

     }

}

   

}

Explanation:

1) The first one is the Parameterized constructor. It takes an array of character as input, and assigns it to the array of character which is a field in the given class MyString.

2) The second one is also the Parameterized constructor, and it takes a string as input, and converts it to an array of characters, and finally assigns it to the character type field of the class MyString.

3) The third one is the copy constructor, and takes a previous object of the class as input, and assigns its values to the new instance of the class.

4) The fourth function returns the length of the character field of the class MyString.

5) The fifth function returns the character in the character field at the given index. And if Index is more than the length of the arr field, it through the IndexOutOfBoundsException.

7 0
4 years ago
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