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vladimir1956 [14]
3 years ago
7

X+8 > 18 how do you solve it

Mathematics
1 answer:
mixer [17]3 years ago
8 0

Answer:

move eight to the other side of the sign by subtracting it from both sides x>10

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1.5.5 Practice: Modeling: Best Ticket Deal
posledela

The best ticket deal are illustrations of linear equations

The ticket system is a better deal to the max ticket

<h3>How to determine the best ticket deal</h3>

From the complete question, we have the following summary:

  • <u>Ticket System</u>

Charges = $22 per person

Surcharge = $10 per transaction

  • <u>Max Tickets</u>

Charges = $20 per person

Surcharge = $16 per transaction

Assume there would be only one transaction, the linear equations that represent the ticket deals are:

Ticket System: y = 22x + 10

Max Ticket: y = 20x + 16

The costs of ticket for two people in both deals are:

Ticket System: y = 22*2 + 10 = 54

Max Ticket: y = 20*2 + 16 = 56

By comparison;

54 is less than 56

This means that the ticket system is a better deal to the max ticket

Read more about linear equations at:

brainly.com/question/14323743

4 0
2 years ago
When you reverse the digits in a certain two-digit number you decrease its value by 9. Find the number if the sum of its digits
9966 [12]
...The number is 21.
8 0
3 years ago
Find the imaginary and real parts of ​
Mariulka [41]

Answer:

12 \\  -  \\ 8 \\  \div 2389 \times 24 + 85 \\  - 63 \\  \times  {89}^{2 5}   \div  \\  |896|  - 92 \\  =  \\ (7821yx) \\  \div 3698 \\  = 0

7 0
3 years ago
3/8 + -7/8 ???????????
saw5 [17]

Answer:

-0.5 hope this help

Step-by-step explanation:

3 0
3 years ago
The polynomial equation x^4 + x^3 + x^2 + x + 1 = 0 has zero positive real roots. Please select the best answer from the choices
const2013 [10]

There are zero positive real roots for the given polynomial equation x^4 + x^3 + x^2 + x + 1 = 0. This is explained by Descarte's rule of signs. So, the best choice is T (true).

<h3>What is Descarte's rule of signs?</h3>
  • Descarte's rule of signs tells about the number of positive real roots and negative real roots.
  • The number of changes in signs of the coefficients of the terms of the given polynomial f(x) gives the positive real zeros of the polynomial.
  • The number of changes in signs of the coefficients of the terms of the given polynomial when f(-x) gives the negative real zeros of the polynomial.

<h3>Calculation:</h3>

The given polynomial equation is x^4 + x^3 + x^2 + x + 1 = 0

On applying Descarte's rule of signs,

f(x)=x^4 + x^3 + x^2 + x + 1

Since there are no changes in the signs of the coefficients of any of the terms in the above polynomial, the polynomial has no positive real roots.

f(-x)=(-x)^4+(-x)^3+(-x)^2+(-x)+1\\      = x^4-x^3+x^2-x+1

Since there are four changes in the signs of the coefficients of the terms of the given polynomial when f(-x), the polynomial has 4 negative real roots.

Therefore, the given polynomial equation has zero positive real roots. So, the correct choice is T(true).

Learn more about Descarte's rule of signs here:

brainly.com/question/11590228

#SPJ1

5 0
2 years ago
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