X+8 > 18 how do you solve it

jan has a 12-ounce milkshake.Four ounces in the milkshake are vanilla,and the rest is chocolate.What are two equivalent fraction

bagirrra123 [75]

Answer:

In this item, we are given that out of 12 ounces of ingredients comprising the milkshake, there are 4 ounces vanilla. Expressing this into fraction will give us an answer of 4/12. This fraction can be one of the answers. Since we are asked for two fractions, we can simplify 4/12 such that we get an equivalent fraction that is equal to 2/6. Hence, the answers to this question are 4/12 and 2/6.

Step-by-step explanation:

7 0

3 years ago

Help please help me out please

maxonik [38]

Answer:

$-\frac{28}{3}$

Step-by-step explanation:

6 0

2 years ago

Read 2 more answers

A bus travels through the city and stops every mile. The first stop on the route is the 8th Avenue Coffee Shop, which is located

ycow [4]

<span>The student apparently added numbers without taking into account direction. They seem to have added 15 and 25 and divided by 2 to get the horizontal component of the middle stop when they should have added 15 and -25 and divided by 2. A similar mistake was made on determining the vertical component. The middle stop should have been calculated as 5 blocks west and 7 blocks south of the central station. So your answer is C.</span>

5 0

3 years ago

Read 2 more answers

The garden club earned $15, 15 per hour by weeding neighborhood gardens for t hours. A generous donor has agreed to double their

natima [27]

Answer:

The answer should be $30.

7 0

3 years ago

3×

In-s [12.5K]

Answer:

1. x = 39.67

2. x = 15

3. x = 49.29

4. x = -12.8

5. x = 96

6. x = 42

7. x = 36

8. x = 0

9. x = 78

Step-by-step explanation:

Just remember to always isolate the unknown. Here are the solutions to your problem. I will explain each step for the first for you to give you an idea how the others were worked out.

1. $\dfrac{3x}{7}-2 = 15$

Add 2 to both sides to get rid of -2 on the left side.

$\dfrac{3x}{7}-2+(2)=15+(2)///dfrac{3x}{7}=17$

Multiply both sides by 7 to get rid of 7 on the left side.

$\dfrac{3x}{7}\times 7 = 17\times 7\\\\3x = 119$

Divide both sides by 3 to get rid of 3 on the left side.

$\dfrac{3x}{3} = \dfrac{119}{3}\\\\x = 39.67$

You could also transpose everything by the x to the other side of the equation. Just remember that whatever OPERATION used on the original side, must be opposite on the other side. I'll use the second problem to show this.

$\dfrac{2x}{5}+1=7$

Transpose 1 on the left to the right. It is addition on the left, then it would be subtraction on the other side.

$\dfrac{2x}{5}+1=7\\\\\dfrac{2x}{5}=7-1\\\\\dfrac{2x}{5}=6$

Transpose 5 from the left side to the right. It is division on the left, then it would be multiplication on the right.

$\dfrac{2x}{5}=6\\\\2x=6\times 5\\\\2x=30$

Transpose 2 from the left side to the right. It is multiplication on the left, then it would be division on the right.

$2x=30\\\\x=\dfrac{30}{2}\\\\x=15$

Let's move on with the rest now.

3.

$\dfrac{7x}{15}-1=22\\\\\dfrac{7x}{15}=22+1\\\\\dfrac{7x}{15}=23\\\\7x=23\times15\\\\7x=345\\\\x=\dfrac{345}{7}\\\\x=49.29$

4.

$\dfrac{5x}{8}+10=2\\\\\dfrac{5x}{8}=2-10\\\\\dfrac{5x}{8}=-8\\\\5x=-8\times8\\\\5x=-64\\\\x=\dfrac{-64}{5}\\\\x=-12.8$

5.

$\dfrac{x}{6}+4=20\\\\\dfrac{x}{6}=20-4\\\\\dfrac{x}{6}=16\\\\x=16\times6\\\\x=96$

6.

$\dfrac{x}{3}-4=10\\\\\dfrac{x}{3}=10+4\\\\\dfrac{x}{3}=14\\\\x=3\times14\\\\x=42$

7.

$\dfrac{x}{6}+2=8\\\\\dfrac{x}{6}=8-2\\\\\dfrac{x}{6}=6\\\\x=6\times6\\\\x=36$

8.

$\dfrac{x}{9}+8=8\\\\\dfrac{x}{9}=8-8\\\\\dfrac{x}{9}=0\\\\x=0\times9\\\\x=0$

9.

$\dfrac{x}{6}+7=20\\\\\dfrac{x}{6}=20-7\\\\\dfrac{x}{6}=13\\\\x=13\times6\\\\x=78$

6 0

3 years ago