A square has four corners.
Answer:
The absolute minimum value of the function over the interval [0,7] is -18.
Step-by-step explanation:
The given function is
Differentiate f(x) with respect to x.
Equate f'(x)=0 to find the critical points.
The critical point is x=3.
Differentiate f'(x) with respect to x.
Since f''(x)>0 for all values of x, therefore the critical point is the point of minima and the function has no absolute maximum value.
3 ∈ [0,7]
Substitute x=3 in the given function to find the absolute minimum value.
Therefore the absolute minimum value of the function over the interval [0,7] is -18.
2/7 because both 8 and 28 are divisible by 4