You want to stain the lateral faces of the wooden chest shown. Find the area that you want to stain in square inches.

1 answer:

3 0

The surface area of the cube-shaped wooden chest which has the side edges of 4 feet shown is 96 square inches.

<h3>What is the surface area of a cube?</h3>

Surface area of cube is the sum of the area of each face by which it is enclosed. The surface area of cube can be calculated with the following formula;

$A=6a^2$

Here, (<em>a</em>) is the length of side of the cube.

You want to stain the lateral faces of the wooden chest shown. Find the area that you want to stain in square inches.

A cube-shaped wooden chest with side edges of 4 feet. Thus the surface area of it is,

$A=6a^2\\A=6(4)^2\\A=96\rm\; ft^2$

Thus, the surface area of the cube-shaped wooden chest which has the side edges of 4 feet shown is 96 square inches.

Learn more about the surface area of cube here;

brainly.com/question/1091166

#SPJ1

You might be interested in

Write a verbal problem that involves subtracting 4 liters.

Alona [7]

A kiddy pool going over it’s limit so you have to subtract 4 liters to get to the safe level bar.

8 0

2 years ago

Suppose for a cookout you need to make 100 hamburgers. YOu know that 2 pounds will make 9 hamburgers. HOw many pounds will you n

Citrus2011 [14]

$\bf \begin{array}{ccll}
lbs&burgers\\
\text{\textemdash\textemdash\textemdash}&\text{\textemdash\textemdash\textemdash}\\
2&9\\
x&100
\end{array}\implies \cfrac{2}{x}=\cfrac{9}{100}\implies \cfrac{2\cdot 100}{9}=x$

8 0

2 years ago

Mary got a graduation gift of $2000 and will put it at a

White raven [17]

the formula is simple interest = Price x rate x time

$2000 x 5 x 10% with is1000

7 0

2 years ago

What is the solution for this problem?

tino4ka555 [31]

Answer: The vertical asymptoms are " x = 3" and " x = -3 " .
__________________________________________________
The answer is: " x = ± 3 " .
__________________________________________________

Explanation:
________________________________________________________
The "denominator" cannot equal "0" ; since one cannot "divide by "0" ;

So; set the "denominator" equal to "0" ;
________________________________________________________

→ " x² − 9 <span>= 0 " ; Solve for all values of "x" ;
</span>
Add "9" to each side of the equation:

→ x² − 9 + 9 = 0 + 9 ;

to get:

→ x² = 9 ;

Take the square root of each side of the equation;
to isolate "x" on one side of the equation; & to solve for "x" ;

→ √(x²) = √9 ;

→ |x| = 3 ;

→ x = <span>± 3 .
</span>__________________________________________________
Answer: The vertical asymptoms are " x = 3" and " x = -3 " .
__________________________________________________
The answer is: " x = ± 3 " .
__________________________________________________

3 0

3 years ago

Can someone pls help me with this problem?

Alex787 [66]

<u></u>

For the first blank, since the output increases by 5 for each increase of 1 for the input, the answer is 13+2(5) = 23.
For the second blank, since the output increased by 10 compared to 23, the input increased by 2. So, the answer is 5 + 2 = 7.
We know the output is of the form 5x+b for some constant b. If we test input of 1 and an output of 3, we get an input of 1 gives 5+b, which is equal to 3, meaning b=-2. So, the answer is 5x-2.

7 0

1 year ago