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pashok25 [27]
3 years ago
7

Help Me With This Question Please! I'm Having A Hard Time Answering This Question! :(

Mathematics
1 answer:
oksano4ka [1.4K]3 years ago
3 0

Answer:

15b square is the answer

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Answer:

roots: -4 and 7

Step-by-step explanation:

where the graph crosses the x axis is where the roots are located

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A cube has a volume of 8 cubic inches what is the length of each edge of the cubes
m_a_m_a [10]
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Let P2 denote the vector space of all polynomials with degree less than or equal to 2. (a) Show that B = {1 + x + x 2 , 1 + 2x −
nirvana33 [79]

Answer:

The answer is in the the attachment

Step-by-step explanation:

The question you posted was incomplete but i believe below is the complete question;

Let P2 denote the vector space of all polynomials with degree less than or equal to 2. (

a) Show that B = {1 + x + x 2 , 1 + 2x − x 2 , 1 − 2x − x 2} is a basis for P2.

(b) Find the coordinate vector of p(x) = 1 + 2x + 3x 2 relative to the basis B

The answer is explained in the attachments.

7 0
3 years ago
Given that x-1 and x+2 are factors of f(x)=x³+px+q where p and q are integers, find p and q. Hence, find the remainder when x³+p
alexandr1967 [171]

Answer:

  • p = -3
  • q = 2
  • remainder = 4

Step-by-step explanation:

We want to find the constants 'a', 'p', and 'q' such that ...

  (x -a)(x -1)(x +2) ≡ x³ +px +q

  (x -a)(x² +x -2) ≡ x³ +px +q

  x³ +x² -2x -ax² -ax +2a ≡ x³ +px +q

This gives rise to three equations:

  1 -a = 0 . . . . coefficient of x²

  -2 -a = p . . . coefficient of x

  2a = q . . . . . constant

The first of these tells us a=1. Then, p=-3 and q=2.

The values of p and q are -3 and 2, respectively.

__

The remainder from division by (x+1) is the value of the cubic for x=-1. That value is ...

  (-1)³ -3(-1) +2 = -1 +3 +2 = 4

The remainder from division by (x+1) is 4.

7 0
2 years ago
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