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Nastasia [14]
3 years ago
14

The formula for finding the perimeter of an equilateral triangle is P=3s. How can you transform the formula so that it can be us

ed to determine the length of one side of the triangle when given the perimeter?
A) 3P=s
B) P/s=3
C) Ps=3
D) P/3=s
Mathematics
1 answer:
tiny-mole [99]3 years ago
3 0
If the formula is P = 3s, then to find side length (s) the formula will become...

s = P/3

answer D
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IM DOING A TEST!<br><br> Idk how to do this help<br> Please try
goldenfox [79]

Answer:

1 is 102

2 is 78

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7 0
4 years ago
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Mom put plums and apples onto a plate. The ratio of the number of plums to the number of apples was 3:2. How many fruit did mom
Delvig [45]

Answer:

30 fruits

Step-by-step explanation:

Let

x ----> number of plums on the plate

y ----> number of apples on the plate

we know that

The ratio of the number of plums to the number of apples was 3:2

so

\frac{x}{y} =\frac{3}{2}

x=1.5y ----> equation A

After Ed took 6 plums from the plate, the number of plums remaining on the plate became the same as the number of apples

so

x-6=y ----> equation B

substitute equation A in equation B

1.5y-6=y

solve for y

1.5y-y=6\\0.5y=6\\y=12

Find the value of x

x=1.5(12)=18

therefore

Mon put on the table

x+y=18+12=30\ fruits

5 0
3 years ago
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= 2. Given the quadratic equation 3x2 – 8x + k = 0 has no real roots. Find the range of values of k.
VashaNatasha [74]

\text{If there  are no real roots, then}\\\\~~~~~\text{Discriminant} < 0\\\\\implies b^2 -4ac < 0\\\\\implies (-8)^2 -4 \cdot 3 k < 0\\\\\implies 64-12k < 0\\\\\ \implies 12k > 64\\\\\implies k > \dfrac{64}{12}\\\\\implies k > \dfrac{16}3\\\\\text{Interval,}~ \left( \dfrac{16}3, ~\infty\right)

6 0
2 years ago
Please help What is the value of this expression when a = 7 and b = -4? |2a| - b/ 3
belka [17]

Answer:

46/3

Step-by-step explanation:

|2a| - b/3

Plug in the values and evaluate.

|2(7)| - (-4)/3

|14| + 4/3

Apply | a | = a

14 + 4/3

42/3 + 4/3

= 46/3

3 0
3 years ago
I’m confused and don’t have an angle tool to even try to do the question
yanalaym [24]
<h3>Answer:   40</h3>

=================================================

Explanation:

JQ is longer than QN. We can see this visually, but the rule for something like this is the segment from the vertex to the centroid is longer compared to the segment that spans from the centroid to the midpoint.

See the diagram below.

The ratio of these two lengths is 2:1, meaning that JQ is twice as long compared to QN. This is one property of the segments that form when we construct the centroid (recall that the centroid is the intersection of the medians)

We know that JN = 60

Let x = JQ and y = QN

The ratio of x to y is x/y and this is 2/1

x/y = 2/1

1*x = y*2

x = 2y

Now use the segment addition postulate

JQ + QN = JN

x + y = 60

2y + y = 60

3y = 60

y = 60/3

y = 20

QN = 20

JQ = 2*y = 2*QN = 2*20 = 40

--------------

We have

JQ = 40 and QN = 20

We see that JQ is twice as larger as QN and that JQ + QN is equal to 60.

7 0
3 years ago
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