The formula for finding the perimeter of an equilateral triangle is P=3s. How can you transform the formula so that it can be us
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The points of intersection are (-2, -2) and (5, 5), so clearly y = x. This reduces the choices to the first and third ones.
Since x-4 is the denominator of all choices, its value at the point (5, 5) will be 1. Hence you need to find the choice that has a numerator of 5 when x=5.
The first choice has a numerator of -5-10 = -15, so that's not it.
The third choice has a numerator of -5+10 = 5, so that's the one you're looking for.
The best choice is the third one, ...
... y = negative x plus ten divided by the quantity x minus four , y = x
