Ask question

Ask question

All categories

1 year ago

8

Manny has a garden that is 12 feet long and 9 feet wide. What is the perimeter of

1 answer:

Julli [10]1 year ago

4 0

Answer:

42 ft

Step-by-step explanation:

2(L + W ) = P

2 (12 + 9) = P

2 (21) = P

42 = P

P = 42

You might be interested in

What is the first step you will use to solve this equation:

Verizon [17]

Subtract 4x from both sides

4x +2 = 7x - 13 would then simplify to

3x - 13 = 2 ( you can switch the problem around as long as you dont switch the variables around )

then you have to + 13 which simplifies to

3x = 15

then you divide by 3 which equals

x=5

5 0

2 years ago

A toy train makes 10 laps around a track in 12 minutes. hpw me my laps per hour is that.

marusya05 [52]

Answer:

50

Step-by-step explanation:

3 0

2 years ago

Read 2 more answers

2+2= I NEED HELP<br><br><br> 40 points if you answer

andrew11 [14]

Answer:

4 IS THE ANSWER

BRAINLEST??

8 0

2 years ago

Read 2 more answers

Suppose we roll a fair die and let X represent the number on the die. (a) Find the moment generating function of X. (b) Use the

Likurg_2 [28]

Answer:

(a) moment generating function for X is $\frac{1}{6}\left(e^{t}+e^{2 t}+e^{2 t}+e^{4 t}+e^{5 t}+e^{6 t}\right)$

(b) $\mathrm{E}(\mathrm{X})=\frac{21}{6} \text { and } E\left(X^{2}\right)=\frac{91}{6}$

Step-by step explanation:

Given X represents the number on die.

The possible outcomes of X are 1, 2, 3, 4, 5, 6.

For a fair die, $P(X)=\frac{1}{6}$

(a) Moment generating function can be written as $M_{x}(t)$ .

$M_x(t)=\sum_{x=1}^{6} P(X=x)$

$M_{x}(t)=\frac{1}{6} e^{t}+\frac{1}{6} e^{2 t}+\frac{1}{6} e^{3 t}+\frac{1}{6} e^{4 t}+\frac{1}{6} e^{5 t}+\frac{1}{6} e^{6 t}$

$M_x(t)=\frac{1}{6}\left(e^{t}+e^{2 t}+e^{3 t}+e^{4 t}+e^{5 t}+e^{6 t}\right)$

(b) Now, find $E(X) \text { and } E\((X^{2})$ using moment generating function

$M^{\prime}(t)=\frac{1}{6}\left(e^{t}+2 e^{2 t}+3 e^{3 t}+4 e^{4 t}+5 e^{5 t}+6 e^{6 t}\right)$

$M^{\prime}(0)=E(X)=\frac{1}{6}(1+2+3+4+5+6)$

$\Rightarrow E(X)=\frac{21}{6}$

$M^{\prime \prime}(t)=\frac{1}{6}\left(e^{t}+4 e^{2 t}+9 e^{3 t}+16 e^{4 t}+25 e^{5 t}+36 e^{6 t}\right)$

$M^{\prime \prime}(0)=E(X)=\frac{1}{6}(1+4+9+16+25+36)$

$\Rightarrow E\left(X^{2}\right)=\frac{91}{6}$

Hence, (a) moment generating function for X is $\frac{1}{6}\left(e^{t}+e^{2 t}+e^{3 t}+e^{4 t}+e^{5 t}+e^{6 t}\right)$ .

(b) $\mathrm{E}(\mathrm{X})=\frac{21}{6} \text { and } E\left(X^{2}\right)=\frac{91}{6}$

6 0

2 years ago

3a+5b/3c-5d =3a -5b/3c- 5d

jenyasd209 [6]

Answer:

-30bc + 50bd

Step-by-step explanation:

3a + 5b/3c - 5d = 3a - 5b/3c - 5d

(3c - 5d)(3a - 5b) = (3a + 5b)(3c - 5d)

9ca - 15bc - 15da + 25db = 9ac - 15ad + 15bc - 25bd

9ca -15bc - 15da + 25db - 9ac + 15ad - 15bc + 25bd

9ca and -9ac and -15da and 15ad cancel each other out, so

-30bc + 50db is left

5 0

2 years ago