Hmm, it actually doesn't exist because at x=3, that is where the absoluve value turns into 0. the graph has a point at x=3 and there is no slope of a pointy part of a function. I mean the slope is undinfed, it is DNE
the value of x for the right triangle is 60
Step-by-step explanation:
Answer:
Yes, it does.
Step-by-step explanation:
Every regular shaped figure will have rotational symmetry, since they are built with identical segments all around.
To find the answer, ask yourself « If I rotate the shape, is there a time where I’ll find the exact same shape again with a different angle? »
So, a square has rotational symmetry, but not a rectangle.
A equilateral triangle has rotational symmetry, but not any other type of triangle.
Set h =11
11=-5t^2+25t+1
-5t^2+25t-10=0
Now use quadratic formula to solve for t
t=[-b+\-sqrt(b^2-4ac)]/(2a)
t= [-25+\-sqrt((25)^2-4(-5)(-10))]/2(-5)
t= .438sec and 4.562sec
