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zlopas [31]
3 years ago
9

Find the product of (x + 3)(x − 3)

Mathematics
2 answers:
leonid [27]3 years ago
8 0

Answer:

The product of (x+3)(x-3) is x²-9

Step-by-step explanation:

Given: (x+3)(x-3)

We need to find the product of the two factor.

Using distributive property

(a+b)(c+d) = ac+ad+bc+bd

(x+3)(x-3)=x(x-3)+3(x-3)

\Rightarrow x^2-3x+3x-9

Cancel like terms

\Rightarrow x^2-9

Hence, The product of (x+3)(x-3) is x²-9

blsea [12.9K]3 years ago
3 0
Let's run through the steps

1. x(x+3)+(x+3)-3    ----------------------------    Distribute
2. x^{2} +3x-3x-9   ---------------     Simplify
3. x^{2} -9   -------------------------     Simplify


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x = 45 degrees

Step-by-step explanation:

The angles in a triangle adds up to 180 degrees

105 + 30 + x = 180

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x = 180-135=45

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3 years ago
Will the border line of the graph of y < - x2 + 4x + 5 be a solid line or a broken
Free_Kalibri [48]

Step-by-step explanation:

When the inequality uses < or >, it is a broken line.

For the point (0, 0) it means that x = 0 and y = 0.

Since (0) < (0)² + 4(0) + 5 is true, the point is part of the solution.

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2 years ago
Write 7.75 x 10^-3 in standard notation​
Natasha_Volkova [10]

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Move the decimal so there is one non-zero digit to the left of the decimal point. The number of decimal places you move will be the exponent on the 10. If the decimal is being moved to the right, the exponent will be negative. If the decimal is being moved to the left, the exponent will be positive.

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Line r is parallel to line t. Find m&lt;6
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Given: ∆ABC, m∠C = 90° CB = 8, m∠B = 38º Find the area of a circumscribed circle. Find the area of the inscribed circle.
vitfil [10]

Answer:

Circumscribed circle: Around 80.95

Inscribed circle: Around 3.298

Step-by-step explanation:

Since C is a right angle, when the circle is circumscribed it will be an inscribed angle with a corresponding arc length of 2*90=180 degrees. This means that AB is the diameter of the circle. Since the cosine of an angle in a right triangle is equivalent to the length of the adjacent side divided by the length of the hypotenuse:

\cos 38= \dfrac{8}{AB} \\\\\\AB=\dfrac{8}{\cos 38}\approx 10.152

To find the area of the circumscribed circle:

r=\dfrac{AB}{2}\approx 5.076 \\\\\\A=\pi r^2\approx 80.95

To find the area of the inscribed circle, you need the length of AC, which you can find with the Pythagorean Theorem:

AC=\sqrt{10.152^2-8^2}\approx 6.25

The area of the triangle is:

A=\dfrac{bh}{2}=\dfrac{8\cdot 6.25}{2}=25

The semiperimeter of the triangle is:

\dfrac{10.152+6.25+8}{2}\approx 24.4

The radius of the circle is therefore \dfrac{25}{24.4}\approx 1.025

The area of the inscribed circle then is \pi\cdot (1.025)^2\approx 3.298.

Hope this helps!

6 0
3 years ago
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