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oksian1 [2.3K]
4 years ago
11

Yeloe Corporation sells 400 shares of common stock being held as an investment. The shares were acquired six months ago at a cos

t of $60 a share. Yeloe sold the shares for $40 a share. The entry to record the sale entails a Select one: a. debit to Cash of $16,000, a debit to Loss on Sale of Stock Investments of $8,000, and a credit to Stock Investments of $24,000 b. debit to Cash of $16,000, and a credit to Stock Investments of $16,000 c. debit to Stock Investments of $16,000, a debit to Loss on Sale of Stock Investments of $8,000, and a credit to Cash of $24,000 d. debit to Cash of $24,000, a credit to Gain on Sale of Stock Investments of $8,000, and a credit to Stock Investments of $16,000
Business
1 answer:
guajiro [1.7K]4 years ago
6 0

Answer:

a.

Explanation:

Cash (400*40)              Dr.$16,000

Loss on sale of stock investments (400*40-400*600  Dr.$8,000

Stock Investments  (400*60)                                          Cr.$24,000

As the stock was sold $20 below its purchase price therefore $20*400 will be recorded as loss on investments.The loss on investments and Cash will be debited and investments have decreased therefore credited.

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The rate at which revenue was generated​ (in millions of dollars per​ year) for a certain company for the years 2010 through 201
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The revenue of a company represents the income generated by the company within a time frame. The total revenue generated by the company from the start of 2010 to the start of 2016 is $39.16 billion

Given that:

f(t) = 348e^{0.22t}  10 \le t \le 16

First, we calculate the integral

\int\limits^{16}_{10} {f(t)} \, dt

This is calculated as:

\int\limits^{16}_{10} {f(t)} \, dt = \int\limits^{16}_{10} {348e^{0.22t}} \, dt

Remove the constant

\int\limits^{16}_{10} {f(t)} \, dt = 348\int\limits^{16}_{10} {e^{0.22t}} \, dt

Now, integrate

\int\limits^{16}_{10} {f(t)} \, dt = 348 \times \frac{1}{0.22} (e^{0.22t})|\limits^{16}_{10}

\int\limits^{16}_{10} {f(t)} \, dt = \frac{ 348}{0.22} (e^{0.22t})|\limits^{16}_{10}

Expand

\int\limits^{16}_{10} {f(t)} \, dt = \frac{ 348}{0.22} (e^{0.22\times 16} -e^{0.22\times 10} )

\int\limits^{16}_{10} {f(t)} \, dt = \frac{ 348}{0.22} (e^{3.52} -e^{2.2} )

\int\limits^{16}_{10} {f(t)} \, dt = \frac{ 348}{0.22} \times 24.759

\int\limits^{16}_{10} {f(t)} \, dt = 39164.2

From the question

t = 10 represents the start of 2010.

This means that

t = 16 represents the start of 2016.

So, the interpretation is:

The total revenue from the start of 2010 to the start of 2016 is $39.16 billion

Read more about revenues at:

brainly.com/question/376674

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