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3 years ago

3. What is the slope of the line that contains the

Mathematics

1 answer:

dlinn [17]3 years ago

7 0

Answer:

I think the answer would be -1/2 or D.

Step-by-step explanation:

Use this formula for calculating slope : y2-y1 / x2 - x1

1. label the pairs, 1 and 2

(-6, 1) - ( x1, y1 ) or (4,-4) - (x1, y1)

(4,-4) - ( x2, y2) (-6,1) - (x2, y2)

(the order does not matter)

2. Than plug in your numbers

y2-y1 / x2 -x1 y2-y1 / x2 -x1

-4 - 1 / 4 - (-6) or 1 - (-4) / -6 - 4

= -5/10 or -1/2 = - 5/-10 or -1/2

im only in eight grade so i did my best explaining , and this hope it helps :)

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How do you solve 2x^2+x=-1?

Olin [163]

Answer:

x = 0.2

Step-by-step explanation:

2x^2+x=-1

4x + x = -1

5x = -1

divide by 5

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3 years ago

5. The superintendent of the local school district claims that the children in her district are brighter, on average, than the g

anygoal [31]

Answer:

We conclude that children in district are brighter, on average, than the general population.

Step-by-step explanation:

We are given the following data set:

105, 109, 115, 112, 124, 115, 103, 110, 125, 99

Formula:

$\text{Standard Deviation} = \sqrt{\displaystyle\frac{\sum (x_i -\bar{x})^2}{n-1}}$

where $x_i$ are data points, $\bar{x}$ is the mean and n is the number of observations.

$Mean = \displaystyle\frac{\text{Sum of all observations}}{\text{Total number of observation}}$

$Mean =\displaystyle\frac{1117}{10} = 111.7$

Sum of squares of differences = 642.1

$S.D = \sqrt{\frac{642.1}{49}} = 8.44$

We are given the following in the question:

Population mean, μ = 106

Sample mean, $\bar{x}$ = 111.7

Sample size, n = 10

Alpha, α = 0.05

Sample standard deviation, s = 8.44

First, we design the null and the alternate hypothesis

$H_{0}: \mu = 106\\H_A: \mu > 106$

We use one-tailed(right) t test to perform this hypothesis.

Formula:

$t_{stat} = \displaystyle\frac{\bar{x} - \mu}{\frac{s}{\sqrt{n}} }$

Putting all the values, we have

$t_{stat} = \displaystyle\frac{111.7 - 106}{\frac{8.44}{\sqrt{10}} } = 2.135$

Now,

$t_{critical} \text{ at 0.05 level of significance, 9 degree of freedom } = 1.833$

Since,

$t_{stat} > t_{critical}$

We fail to accept the null hypothesis and reject it. We accept the alternate hypothesis.

We conclude that children in district are brighter, on average, than the general population.

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3 years ago

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Mademuasel [1]

Common difference is -2-5 = -7
first term is 5

a_50 = 5 -7(50-1) = -338

2) d = 3 - (-7) = 10
a = -7

a_110 = -7 + 10(110 - 1) = 1083

d = -27 - (-22) = -5

second -7 - 5= -12
third = -12 - 5 = -17

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3 years ago

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Sergio [31]

Answer: 110

Step-by-step explanation:

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4 years ago

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3 years ago

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