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zimovet [89]
3 years ago
13

Ay a party the number of people who ate meatballs was 11 fewer than 1/3 of the total of people. Five people ate meatballs. Write

the equation and solve
Mathematics
1 answer:
Afina-wow [57]3 years ago
5 0

Answer:

5=1/3x-11

Step-by-step explanation:

Add eleven to each side to get 16=1/3x. Then multiply each side by three to get 48=x, so x=48.

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Franklin rolls a pair of six-sided fair dice with sides numbered 1 through 6.
Zarrin [17]

Answer:

The answer is 7/36.

Step-by-step explanation:

First, you find out how many possible outcomes there are from rolling a pair of dice. On one cube, you can roll a 1,2,3,4,5, or 6; so there are 6 outcomes. Since there are two cubes, you multiply 6 by itself to get a total of 36 possible outcomes. Next, you find the probability of the sum of the numbers rolled being an even number; the possibilities are 2,4,6,8,10, or 12, which is 6/36. The probability of rolling a multiple of 5; the one possibility is just 5, since we already accounted for rolling a 10 as an even number. So that is 1/36. The word <u>or</u> says that we add the two probabilities, so the final answer is 6/36+1/36=7/36.

6 0
3 years ago
Simplify 2(a-3)/(a-4)(a-5)+(a-1)/(3-a)(a-4)+(a-2)/(5-a)(a-3)​
Umnica [9.8K]

Answer:

  \dfrac{5}{x^3-12x^2+47x-60}

Step-by-step explanation:

Though it is not what you have written, we think you want to simplify ...

  \dfrac{2(a-3)}{(a-4)(a-5)}+\dfrac{(a-1)}{(3-a)(a-4)}+\dfrac{(a-2)}{(5-a)(a-3)}\\\\=\dfrac{2(a-3)^2}{(a-3)(a-4)(a-5)}+\dfrac{-(a-1)(a-5)}{(a-3)(a-4)(a-5)}+\dfrac{-(a-2)(a-4)}{(a-3)(a-4)(a-5)}\\\\=\dfrac{2(a^2-6a+9)-(a^2-6a+5)-(a^2-6a+8)}{x^3-12x^2+47x-60}\\\\=\boxed{\dfrac{5}{x^3-12x^2+47x-60}}

_____

When writing a fraction in plain text, parentheses are needed around the entire denominator. The order of operations tells you that a/bc = (a/b)c, not a/(bc).

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3 years ago
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I think the answer is 1.06666666667
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A software company sells an education version (e) and a commercial version (c) of its popular image editing software. During the
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Make 2 equations let x=150 y=600/180000  than plug and chug
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