A function m(t)= m₀e^(-rt) that models the mass remaining after t years is; m(t) = 27e^(-0.00043t)
The amount of sample that will remain after 4000 years is; 4.8357 mg
The number of years that it will take for only 17 mg of the sample to remain is; 1076 years
<h3>How to solve exponential decay function?</h3>
A) Using the model for radioactive decay;
m(t)= m₀e^(-rt)
where;
m₀ is initial mass
r is rate of growth
t is time
Thus, we are given;
m₀ = 27 mg
r = (In 2)/1600 = -0.00043 which shows a decrease by 0.00043
and so we have;
m(t) = 27e^(-0.00043t)
c) The amount that will remain after 4000 years is;
m(4000) = 27e^(-0.00043 * 4000)
m(4000) = 27 * 0.1791
m(4000) = 4.8357 mg
d) For 17 mg to remain;
17 = 27e^(-0.00043 * t)
17/27 = e^(-0.00043 * t)
In(17/27) = -0.00043 * t
-0.4626/-0.00043 = t
t = 1076 years
Read more about Exponential decay function at; brainly.com/question/27822382
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Answer:
the answer should be 2.04
Step-by-step explanation:
30 in the ratio 3:2
3:2....added = 5
3/5(30) = 90/5 = 18
2/5(30) = 60/5 = 12
so 30 in the ratio 3:2 is 18:12
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31.50 in the ratio 3:4
3:4...added = 7
3/7(31.50) = 94.5/7 = 13.50
4/7(31.50) = 126/7 = 18
31.50 in the ratio 3:4 is 13.50:18
Look it up on desmos, it’s an online graphing calculator, you’re welcome!
