Answer:
A i think but i think not also try it
Number 3 is A and number 4 is G, do you want to know how I got my answer...
Consider a homogeneous machine of four linear equations in five unknowns are all multiples of 1 non-0 solution. Objective is to give an explanation for the gadget have an answer for each viable preference of constants on the proper facets of the equations.
Yes, it's miles true.
Consider the machine as Ax = 0. in which A is 4x5 matrix.
From given dim Nul A=1. Since, the rank theorem states that
The dimensions of the column space and the row space of a mxn matrix A are equal. This not unusual size, the rank of matrix A, additionally equals the number of pivot positions in A and satisfies the equation
rank A+ dim NulA = n
dim NulA =n- rank A
Rank A = 5 - dim Nul A
Rank A = 4
Thus, the measurement of dim Col A = rank A = five
And since Col A is a subspace of R^4, Col A = R^4.
So, every vector b in R^4 also in Col A, and Ax = b, has an answer for all b. Hence, the structures have an answer for every viable preference of constants on the right aspects of the equations.
Answer:
The answer is 234
Step-by-step explanation:
The area shaded in green is 864 cm²
<h3>Similar figures</h3>
Similar figures, corresponding angles are congruent and the sides are ratio of each other. Therefore,
AB / PQ = CD / RS
30 / 10 = 24 / RS
30RS = 240
RS = 240 / 30
RS = 8 cm
let find the height of trapezium PQRS.
AB / PQ = 36 / h
30 / 10 = 36 / h
30h = 360
h = 360 / 30
h = 12 cm
Therefore,
area of the green portion = area of ABCD - area of PQRS
<h3>Area of a trapezium</h3>
Therefore,
area of ABCD = 1 / 2(24 + 30)36 = 1 / 2 (54)36 = 1944 / 2 = 972 cm²
area of PQRS = 1 / 2(10 + 8)12 = 1 / 2(18)12 = 216 / 2 = 108 cm²
Area of the green portion = 972 - 108 = 864 cm²
learn more on trapezium here: brainly.com/question/11961445
