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ludmilkaskok [199]
3 years ago
14

What is the 13th term of this arithmetic sequence? 132, 135, 138, 141, …

Mathematics
1 answer:
Marrrta [24]3 years ago
6 0
The rule for this sequence is n + 3. 132 --> 135 is +3, 135 --> 138 is +3, and 138 --> 141 is +3. Let's use this rule until we find the 13th term. 132 (1) 135(2) 138(3) 141(4) 144(5) 147(6) 150(7) 153(8) 156(9) 159(10) 162(11) 165(12) 168(13) 168 is the 13th term in this sequence. I hope this helps!
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gayaneshka [121]

Answer:

40.4%

Step-by-step explanation:

Given data

Initial depth= 5feet

Final depth= 5-3.2+6.6= 8.4feet

Hence the percent change

% change= FInal-initial/final*100

% change= 8.4-5/8.4*100

% change= 3.4/8.4*100

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% change=40.4%

Hence the percent change is 40.4%

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4 years ago
(x + 6)(x + 2) = 60?
Salsk061 [2.6K]

Answer:

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Step-by-step explanation:

x(x+2)+6(x+2)=60

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3 years ago
Brian wants to have $7000 in the bank in 10 years. He deposits $3000 today at 8% interest compounded semiannually,After keeping
AveGali [126]
Total = Principal * ((1 + rate/n)^(n*years)
Total = 3,000 * (1.04)^20
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Here's a calculator to check your work http://www.1728.org/compint.htm
</span>
6 0
4 years ago
Read 2 more answers
This is algebra 2 it’s growth &amp; decay. I need help
Elodia [21]
<h3>Part 1:</h3>

So firstly, remember that the <em>a variable is the initial value.</em> Since we start off with 6.08 billion, <u>6.08 billion is the a variable.</u>

Next, since this is a <em>growth by 1.26%</em>, add 1 and 0.0126 (1.26% in decimal form) together to get 1.0126. <u>1.0126 is the b variable.</u>

Putting it together, <u>the function is A(t)=6.08(1.0126)^t</u>

<h3>Part 2:</h3>

Since 2020 is 20 years from 2000, plug in 20 into the t variable of the prior function to solve:

A(20)=6.08(1.0126)^{20}\\ A(20)=7.81

In context, <u>in 2020 the population will be 7.81 billion.</u>

6 0
4 years ago
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