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Anton [14]
3 years ago
5

You want to determine the concentration of a solid solute dissolved in a specified volume of liquid solvent which of the followi

ng would be the best to use?
a) volume/volume percent
b) molarity
c)mass/mass percent
d)mole fraction
Chemistry
2 answers:
Tresset [83]3 years ago
7 0

The answer is: b) molarity.

Molar concentration (molarity) is a measure of the concentration of a solute in a solution.

Unit for molarity (c = n/V) is the number of moles (n) per litre (V), having the unit symbol mol/L or sometimes mol/dm³.

For example:

m(NaOH) = 80.0 g; mass of solide solute.

n(NaOH) = m(NaOH) ÷ M(NaOH).

n(NaOH) = 80 g ÷ 40 g/mol.

n(NaOH) = 2 mol.

V(NaOH) = 500 mL ÷ 1000 mL/L.

V(NaOH) = 0.5 L; a specified volume of liquid solvent.

c(NaOH) = n(NaOH) ÷ V(NaOH).

c(NaOH) = 2 mol ÷ 0.5 L.

c(NaOH) = 4 mol/L.

Natali [406]3 years ago
6 0
Generally, chemists prefer to use morality (B) because it only invovles measuring the final volume of the solution and amount of moles of the solute

Hope this helps
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Here is the information: A 1.2516 gram sample of a mixture of CaCO3 and Na2SO4 was analyzed by dissolving the sample and adding
tiny-mole [99]

Answer:

93,32 % (w/w)

Explanation:

The Ca²⁺ of CaCO₃ was completely precipitate to CaC₂O₄ that results in H₂C₂O₄. The titration of this one is:

3H₂C₂O₄ + 2H⁺ + MnO₄⁻ → Mn²⁺ + 4H₂O + 6CO₂

As you required 35,62mL of 0,1092M MnO₄⁻, the moles of H₂C₂O₄ are:

0,03562L×\frac{0,1092M}{L} =

3,890x10⁻³mol of MnO₄⁻×\frac{3molH_{2}C_{2}O_{4}}{1mol MnO_{4}^-} = <em>0,01167 mol of H₂C₂O₄</em>

The number of moles of CaCO₃ are the same number of moles of H₂C₂O₄ because every Ca²⁺ was converted in CaC₂O₄ that was converted in H₂C₂O₄. That means: <em>0,01167 mol of CaCO₃</em>

0,01167 mol of CaCO₃ are:

0,01167 mol of CaCO₃×\frac{100,0869g}{1mol} = <em>1,168 g of CaCO₃</em>

As the mass of the initial mixture is 1,2516 g, the percentage by weight of CaCO₃ is:

\frac{1,168g}{1,2516g}×100 = <em>93,32 % (w/w)</em>

I hope it helps!

7 0
3 years ago
How many grams are in 3.45 moles of CaCl2
Firdavs [7]

Answer:

Explanation:

First we find the Molecular weight of CaCl2

looking at the periodic table the MW of Ca is 40.078 and Cl is 35.453 and the ratio of ca to cl is 1:2 so we multiply cl by 2 which is 35.453*2=70.906

we add them together: 40.078 + 70.906 = 110.984 g/mol

now:

\frac{110.984 grams}{mol} * 3.45 mol

the mol cancels out and we left with 3.45 * 110.984 grams = 382.89 grams

6 0
4 years ago
497.680 to the nearest gram (1 g)
Lelu [443]
14109 is the nearest gram
6 0
4 years ago
Read 2 more answers
Write a net ionic equation for the reaction that occurs when excess hydroiodic acid and chromium(II) carbonate (s) are combined.
LUCKY_DIMON [66]

Answer:

Net ionic equation: 2I⁻(aq) + Cr²⁺(aq) → CrI₂(s)

<h3>Explanation:</h3>
  • A chemical equation shows chemical symbols of compounds known as reactants and compounds known as products in a chemical reaction.
  • The chemical equation between hydroiodic acid and chromium (II) carbonate is given by;

2HI(aq) + CrCO₃(aq) → H₂CO₃(aq) + CrI₂(s)

  • The Ionic equation is an equation that shows all the ions involved in a chemical reaction.
  • In this case, the ionic equation is;

2H⁺ I⁻(aq)+ Cr²⁺ CO₃²⁻(aq) → 2H⁺ CO₃²⁻(aq) + CrI₂(s)

  • The net ionic equation is an equation showing only the ions that take part in the reactions. The ions that do not take part in the chemical reaction known as spectator ions are not shown when writing net ionic equations.
  • Spectator ions are those ions that do not change state after the chemical reaction has taken place. In this case, hydrogen ions and carbonate ions are spectator ions.
  • The net ionic equation is

2I⁻(aq) + Cr²⁺(aq) → CrI₂(s)

6 0
3 years ago
The free rapid movement of electrons in metallic bonds makes them
babunello [35]

Answer:

C: Good conductors of electricity

Explanation:

By definition, Metals have metallic bonds and thus they are good conductors of electricity due to the fact that their electrons in the electron sea are usually free to flow and carry electric current. Thus, the correct answer is option C.

3 0
3 years ago
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