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Anton [14]
3 years ago
5

You want to determine the concentration of a solid solute dissolved in a specified volume of liquid solvent which of the followi

ng would be the best to use?
a) volume/volume percent
b) molarity
c)mass/mass percent
d)mole fraction
Chemistry
2 answers:
Tresset [83]3 years ago
7 0

The answer is: b) molarity.

Molar concentration (molarity) is a measure of the concentration of a solute in a solution.

Unit for molarity (c = n/V) is the number of moles (n) per litre (V), having the unit symbol mol/L or sometimes mol/dm³.

For example:

m(NaOH) = 80.0 g; mass of solide solute.

n(NaOH) = m(NaOH) ÷ M(NaOH).

n(NaOH) = 80 g ÷ 40 g/mol.

n(NaOH) = 2 mol.

V(NaOH) = 500 mL ÷ 1000 mL/L.

V(NaOH) = 0.5 L; a specified volume of liquid solvent.

c(NaOH) = n(NaOH) ÷ V(NaOH).

c(NaOH) = 2 mol ÷ 0.5 L.

c(NaOH) = 4 mol/L.

Natali [406]3 years ago
6 0
Generally, chemists prefer to use morality (B) because it only invovles measuring the final volume of the solution and amount of moles of the solute

Hope this helps
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solution:

A = 192 x (1/2) ^ (15/5) = 192 x (1/2) ^3 = 192 x 1/8 = 24 mg

 Starting by hitting acetylene with NaNH2 to deprotonate, this C-- will attack the C connected to the Br Sn2 style to lengthen the chain by two carbons.  

Do this same thing again with the other CH of the acetylene and another bromoethaneto get a six carbon chain, namely, 3-hexyne.  

Now, reduce the alkyne to an alkene via H2/Pd/C, and that gives 3-hexene.  


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rosijanka [135]
<span>Answer: Correct answer is 507g FeCl2 x (1 mol FeCl2 / 126.8 g FeC2) x (1 mol Fe(OH)2 / 1 mol FeCl2) x (89.8 g Fe(OH)2/ 1 mol Fe(OH)2) = 359 g Fe(OH)2.</span>
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grandymaker [24]

Answer:

Intrusive and Extrusive igneous rocks.

Explanation:

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The igneous rocks are of two different types, namely-

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_________________
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Activation energy Group of answer choices is only required in catabolic reactions that release energy. is not required at all wh
daser333 [38]

Answer:

is used to break reactant bonds and/or make new product bonds.

Explanation:

<em>The correct answer would be that </em><em>activation energy is used to break reactant bonds and/or make new product bonds</em><em>.</em>

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