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Alexxandr [17]
3 years ago
9

The metal lithium has a diagonal relationship with the metal magnesium. true or false.

Chemistry
1 answer:
emmasim [6.3K]3 years ago
6 0
False   .........................................                                                   
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A. draw the structure of the tetrahedral intermediate initially formed in the reaction shown. you do not have to consider stereo
julsineya [31]
The reaction is shown below, Acid protonates the carbonyl oxygen and makes the carbonyl carbon more electrophilic. Water attacks on activated carbonyl group and forms a tetrahedral intermediate.

Intermediate:
                    Structure of Intermediate is shown both in 2-D and 3-D (below attached). 

Carbonyl group is regenerated with the elimination of ethanol.

Reaction is as below, The final product is carboxylic acid.

4 0
3 years ago
How many molecules of water are in 3.8 moles of water?
Salsk061 [2.6K]

Answer:

2.29*10^24 molecules of water

Explanation:

1 molof water =6.022*10^23 molecules of water

therefore

molecules of water = 3.8*6.022*10^23

5 0
3 years ago
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Which of the following statements is not correct?
Lilit [14]

Answer:

It's 4.1 moles Li2O = 94 g on Odyssey ware

8 0
3 years ago
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How many grams of mercury are needed to react completely with 157g of sulfur to form hgs?
Salsk061 [2.6K]
<span>To solve this we need to balance the equations first.
 So Hg + S --> HgS is balanced
 One mole of Hg requires one mole of S to form one mole of HgS.
 Number of moles of Sulphur = mass/ molar mass = 157/32 = 4.906
So 4.90 moles of S reacts with 4.90 moles of Hg.
Hence there are 4.90 moles of 4.90 of Hg.
 Mass = number of moles * molar mass of Hg
Mass = 4.906 * 200.59 = 982.891g</span>
8 0
3 years ago
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What is the wavelength of light with 2.89 x 10-19 J of energy? (The speed of
Alika [10]

Let's see

\\ \rm\rightarrowtail E=hv

\\ \rm\rightarrowtail E=\dfrac{hc}{\lambda}

  • lambda is wavelength
  • h is Planck constant
  • c is velocity of sound in air
  • E in energy

\\ \rm\rightarrowtail \lambda=\dfrac{hc}{E}

\\ \rm\rightarrowtail \lambda=\dfrac{6.626\times 10^{-34}\times 3\times 10^8}{2.89\times 10^{-19}}

\\ \rm\rightarrowtail \lambda=6.878\times 10^{-7}m

\\ \rm\rightarrowtail \lambda=68.8\mu m

3 0
2 years ago
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