Answer:
Actual yield = 86.5g
Explanation:
Percent yield = 82.38%
Theoretical yield = 105g
Actual yield = x
Equation of reaction,
CaCO₃ + HCl → CaCl₂ + CO₂ + H₂O
Percentage yield = (actual yield / theoretical yield) * 100
82.38% = actual yield / theoretical yield
82.38 / 100 = x / 105
Cross multiply and make x the subject of formula
X = (105 * 82.38) / 100
X = 86.499g
X = 86.5g
Actual yield of CaCl₂ is 86.5g
Answer:
63.5 w isvthebanswerok is th answer
Answer:
Exocytosis
Explanation:
Some molecules are simply too big to move via a transport protein or the plasma membrane. To carry these macromolecules in or out of the cell, cells employ two more active transport pathways. Macromolecules or big particles are transported across the plasma membrane via Vesicles transport or other cytoplasmic structures. They are of two types, Endocytosis and Exocytosis
From the given information, Exocytosis is the right answer.
It is the process of vesicles combining with the plasma membrane thereby releasing their contents to the exterior of the cell. When a cell creates components for export, such as proteins, or when it gets rid of a waste product or a toxin, exocytosis occurs. Exocytosis is the process by which newly generated membrane proteins and membrane lipids are transported on top of the plasma membrane.
Answer:
C₆H₁₂O₆ and O₂
Explanation:
To know which option is correct, it important that we know the concepts of chemical equation .
A chemical equation gives us an expression of a chemical reaction in terms of symbols and formula. There are two sides to every equation. The side bearing the reactant and the side bearing the product.
The reactant is located on the left side and the product is located on the right side.
Reactant —> Product
With the above information, let us answer the question given above.
6CO₂ + 6H₂O —> C₆H₁₂O₆ + 6O₂
The products are located on the right side of the equation.
Thus, the products of the reaction is C₆H₁₂O₆ and O₂
Easy (:
C₃H₈ (g) + O₂ (g) ---> CO₂ (g) + H₂O
1 C₃H₈ (g) + 5 O₂ (g) ---> 3 CO₂ (g) + 4 H₂O
With this there is the same amount of elements on each side (You take the larger number in front and multiply it by whats after it. So you have 3 C, 8 H, and 10 O on one side, and then the next mirrors is with 3 C, 8 H, and 10 O.
