Explanation:
In a magnetic field, the radius of the charged particle is as follows.
r = ![\frac{mv}{qB}](https://tex.z-dn.net/?f=%5Cfrac%7Bmv%7D%7BqB%7D)
where, m = mass, v = velocity
q = charge, B = magnetic field
Therefore, q will be calculated as follows.
q = ![\frac{mv}{rB}](https://tex.z-dn.net/?f=%5Cfrac%7Bmv%7D%7BrB%7D)
= ![\frac{6.6 \times 10^{-27} \times 5.3 \times 10^{5}}{0.014 m \times 0.78 T}](https://tex.z-dn.net/?f=%5Cfrac%7B6.6%20%5Ctimes%2010%5E%7B-27%7D%20%5Ctimes%205.3%20%5Ctimes%2010%5E%7B5%7D%7D%7B0.014%20m%20%5Ctimes%200.78%20T%7D)
= ![\frac{34.98 \times 10^{-22}}{0.01092}](https://tex.z-dn.net/?f=%5Cfrac%7B34.98%20%5Ctimes%2010%5E%7B-22%7D%7D%7B0.01092%7D)
= ![3.2 \times 10^{-19} \times \frac{1.0 e}{1.6 \times 10^{-19}C}](https://tex.z-dn.net/?f=3.2%20%5Ctimes%2010%5E%7B-19%7D%20%5Ctimes%20%5Cfrac%7B1.0%20e%7D%7B1.6%20%5Ctimes%2010%5E%7B-19%7DC%7D)
= +2e
Thus, we can conclude that the charge of the ionized atom is +2e.
Answer:
1. V₁ = 2.0 mL
2. V₁ = 2.5 mL
Explanation:
<em>You are provided with a stock solution with a concentration of 1.0 × 10⁻⁵ M. You will be using this to make two standard solutions via serial dilution.</em>
To calculate the volume required (V₁) in each dilution we will use the dilution rule.
C₁ . V₁ = C₂ . V₂
where,
C are the concentrations
V are the volumes
1 refers to the initial state
2 refers to the final state
<em>1. Perform calculations to determine the volume of the 1.0 × 10⁻⁵ M stock solution needed to prepare 10.0 mL of a 2.0 × 10⁻⁶ M solution.</em>
C₁ . V₁ = C₂ . V₂
(1.0 × 10⁻⁵ M) . V₁ = (2.0 × 10⁻⁶ M) . 10.0 mL
V₁ = 2.0 mL
<em>2. Perform calculations to determine the volume of the 2.0 × 10⁻⁶ M solution needed to prepare 10.0 mL of a 5.0 × 10⁻⁷ M solution.</em>
C₁ . V₁ = C₂ . V₂
(2.0 × 10⁻⁶ M) . V₁ = (5.0 × 10⁻⁷ M) . 10.0 mL
V₁ = 2.5 mL
A hydrated substance will decrease in mass when heated since the water is being boiled away.
I hope this helps. Let me know if anything is unclear.
Answer:
D) is the answer please thanks