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Ludmilka [50]
3 years ago
15

Which values are written in proper scientific notation? Check all that apply. –350 –350.00 –3.50 × 104 0.000350 3.50 × 104 3.50

× 10–4 35.0 × 10–5 3,500
Chemistry
2 answers:
Oksanka [162]3 years ago
7 0
-3.50 * 10^4
3.50 * 10^4
3.50 * 10^-4
algol133 years ago
7 0

Answer : The correct options are, -3.50\times 10^{4},3.50\times 10^{4}\text{ and }3.50\times 10^{-4}

Explanation :

Scientific notation : The way or representation of expressing the number that are too big or too small that is written in the decimal form. That means always written in the power of 10 form.

For example : 700 is written in scientific notation as, 7.0\times 10^2

According to the question, -3.50\times 10^{4},3.50\times 10^{4}\text{ and }3.50\times 10^{-4}  are written in proper scientific notation. While the other options are not written in proper scientific notation.

Therefore, the correct options are, -3.50\times 10^{4},3.50\times 10^{4}\text{ and }3.50\times 10^{-4}

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Calculate the concentration of clo2− at equilibrium if the initial concentration of hclo2 is 2. 25×10^−2 m.
jek_recluse [69]

The concentration of ClO₂⁻ at equilibrium if the initial concentration of  HClO₂ is 0.0654.

<h3>What is concentration?</h3>

The concentration of any substance is the quantity of that substance in per square of the space or container.

The reaction is

HClO₂ + H₂O <=> H₃O⁺ + ClO₂⁻

The pH is 0.454 M

Ka = [H₃O⁺][ClO₂⁻ ] / [HClO₂]

2. 25 × 10⁻² m = [x][x] / 0.454-x]

2 + 0.011 - 0.004994 = 0

solve the quadratic equation

x = 0.0654 = [H3O+] = [ClO2-]

pH = -log (H3O+)

pH = -log(0.0654)

pH = 1.2

equilibrium concentrations of

[HClO2] = 0.454 -x = 0.454 -0.0654 = 0.3886 M

[ClO2- ] = x = 0.0654

Thus, the equilibrium concentrations  is 0.0654.

To learn more about concentration, refer to the link:

brainly.com/question/16645766

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What is very fine sediment called
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c the temperature is increased?5)

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Valence Bond theory predicts that tin will use what hybrid orbitals in Snf5 -1​
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Answer:

sp3d

Explanation:

The ground state electronic configuration of tin is written as; [Kr] 5s²4d¹⁰5p². Hybridization is a concept used to explain the combination of orbitals of appropriate energy to produce suitable orbitals that could be used for bonding.

In forming the compound Snf5^ -1, we have to hybridize the following orbitals on tin; 5p, 5d and 6s orbitals. This gives us a set of sp3d hybrid  hence the answer.

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