Hope this help if you need help graphing I would use desmos
Answer:
The location of the point is between Quadrant II and Quadrant III
Step-by-step explanation:
we know that
The abscissa refers to the x-axis and ordinate refers to the y-axis
so
in this problem we have
the coordinates of the point are 
see the attached figure to better understand the problem
The location of the point is between Quadrant II and Quadrant III
I am not quite sure what the question asks for,
But this is what i assume it wants:
Cos A= 0.6489
In this given one, we basically find the size of the angle A
we do cosine inverse on both sides to get the size of the angle A

: It looks like this in the calculator

× cos A=

(0.6489)
(

and cos cancels out)
A=

(0.6489)
A=49.54°
check:
cos 49.54=0.6489 (its right!)
Step-by-step explanation:
take the base square. find the diagonal
16^2+16^2 = 2*16^2= d^2
d= 16√2
half of the diagonal will form the baSe of right triangle of hypotenuse 10. but the base will be 8√2 which is greater than 10. so I feel the slant hr has to be different and more than 10
earnings * 20 percent = 17
earnings * .2 = 17
divide by .2 on each side
earnings = 17/.2
earnings = $85.00