Answer:
P(X 
74) = 0.3707
Step-by-step explanation:
We are given that the score of golfers for a particular course follows a normal distribution that has a mean of 73 and a standard deviation of 3.
Let X = Score of golfers
So, X ~ N(
)
The z score probability distribution is given by;
Z = 
~ N(0,1)
where, 
= population mean = 73
= standard deviation = 3
So, the probability that the score of golfer is at least 74 is given by = P(X 74)
P(X 74) = P( 
) = P(Z 0.33) = 1 - P(Z < 0.33)
= 1 - 0.62930 = 0.3707
Therefore, the probability that the score of golfer is at least 74 is 0.3707 .
Answer:
All the options are correct
Answer:
Proved,
P(A∪B)=0.72
Step-by-step explanation:
Sue travels by bus or walks when she visits the shops.
Probability( catch the bus to the shop ), P(A) = 0.4
Probability( catch the bus from the shop ), P(B) = 0.7
Both A and B are independent events.
Therefore,
P(A∩B) = 0.4×0.7
= 0.28
Probability Sue walks one way = 1 - P(A∩B)
= 1 - 0.28
= 0.72
Hence, the probability that Sue walks at one way is 0.72
Answer:
I u having ur online test or papers
