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bazaltina [42]
3 years ago
8

How do you write an equation in standard form given point (-1,6) and (3,-2)?

Mathematics
1 answer:
kolbaska11 [484]3 years ago
7 0
Find the slope
y-y1=m(x-x1)
F(x)=-2x+4
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What is the equation of the line that passes through the point (-5,-2) and has a slope of -6/5
tatyana61 [14]

Answer:

The answer is

<h2>y =  -  \frac{6}{5} x - 8  \\</h2>

Step-by-step explanation:

To find an equation of a line in point slope form when given the slope and a point we use the formula

y -  y_1 = m(x -  x_1) \\

where

m is the slope

( x1 , y1) is the point

From the question the point is (-5,-2) and the slope is - 6/5

The equation of the line is

y + 2 =  -  \frac{6}{5} (x + 5) \\ y + 2  =  -  \frac{6}{5} x - 6 \\ y =  -  \frac{6}{5} x - 6 - 2

We have the final answer as

y =  -  \frac{6}{5} x - 8  \\

Hope this helps you

5 0
3 years ago
Jackrabbits are capable of reaching speeds up to 40 miles per hour. How fast is this in feet per second? (Round to the nearest w
Sonja [21]
To solve this problem, we are going to use a scientific/mathematics strategy called Dimensional Analysis.

40 miles / 1 hour * 5280 feet / 1 mile = 211200 feet / 1 hour

211200 feet / 1 hour * 1 hour / 60 minutes = 3520 feet/ 1 minute

3520 feet / 1 minute * 1 minute / 60 seconds = approximately 59 feet / 1 second


Jackrabbits travel approximately 59 feet per second, when rounded to the nearest whole number.

8 0
3 years ago
For an art project, Kelvin cut a 4-foot piece of yarn into pieces. He then measured the length of each piece of yarn to the near
oksian1 [2.3K]

Answer:

I think answers is

D

label the x-axis "Pieces of Yarn," and label the y-axis "Length (inches

3 0
3 years ago
Solve the following equation for y.<br>x-5y=-18<br>​
olganol [36]

Answer:

y=15x+185

Step-by-step explanation:

Step 1: Add -x to both sides.

x−5y+−x=−18+−x

−5y=−x−18

Step 2: Divide both sides by -5.

−5y−5=−x−18−5

y=15x+185

6 0
3 years ago
Consider the function g(x) = 10/x
ss7ja [257]
<span><span>The correct answers are:
</span><span>(1) The vertical asymptote is x = 0
(2) The horizontal asymptote is y = 0

</span><span>Explanation:
</span><span>(1) To find the vertical asymptote, put the denominator of the rational function equals to zero.

Rational Function = g(x) = </span></span>\frac{10}{x}<span>

Denominator = x = 0

Hence the vertical asymptote is x = 0.

(2) To find the horizontal asymptote, check the power of x in numerator against the power of x in denominator as follows:

Given function = g(x) = </span>\frac{10}{x}<span>

We can write it as:

g(x) = </span>\frac{10 * x^0}{x^1}<span>

If power of x in numerator is less than the power of x in denomenator, then the horizontal asymptote will be y=0.
If power of x in numerator is equal to the power of x in denomenator, then the horizontal asymptote will be y=(co-efficient in numerator)/(co-efficient in denomenator).
If power of x in numerator is greater than the power of x in denomenator, then there will be no horizontal asymptote.

In above case, 0 < 1, therefore, the horizontal asymptote is y = 0
</span>
5 0
3 years ago
Read 2 more answers
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