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Triss [41]
3 years ago
5

Determine the horizontal, vertical, and slant asymptotes: y=x2+2x-3/x-7

Mathematics
1 answer:
densk [106]3 years ago
3 0

Answer:

  • vertical asymptote: x = 7
  • slant asymptote: y = x+9

Step-by-step explanation:

The vertical asymptotes are found where a denominator factor is zero (and there is no corresponding numerator factor to cancel it). Here, that is at x = 7.

There is no horizontal asymptote because the numerator is of higher degree than the denominator.

When you divide the numerator by the denominator, you get ...

  y = (x +9) +60/(x -7)

Then when x gets large, the behavior is governed by the terms not having a denominator: y = x +9. This is the equation of the slant asymptote.

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HELP ASAP ILL GIVE YOU BRAINLEST
stellarik [79]

Answer:

f(x) = (8/3)x(x - 1).

Step-by-step explanation:

The vertex form of the function is

y = a(x - 1/2)^2 - 2/3   where a is some constant.

Now the roots are 0 and 1 so

For  x = 0

0 =  a(-1/2)^2 - 2/3

1/4 a = 2/3

a = 2/3 / 1/4  = 8/3.

So the function is

f(x) = (8/3)(x - 1/2)^2 - 2/3.

3 f(x) = 8(x - 1/2)^2 - 2

= 8(x^2 - x + 1/4) - 2

=  8x^2 - 8x + 2 - 2

3 f(x) = 8x(x - 1)

f(x) = (8/3)x(x - 1).

5 0
3 years ago
Read 2 more answers
What is the value of the expression below when a = 3 and b = 7?
svp [43]

Answer:

42

Step-by-step explanation:

9^2*7-2*7

56-14

42

I hope this helps.

6 0
3 years ago
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Determine which trig ratio you would use to find the height of the tree.
Viktor [21]
Sin= p/h , cos= b/h , tan= p/b
3 0
3 years ago
Rearrange x = 3g + 2 to make g the subject​
lord [1]

Answer:

g=\frac{x}{3} -\frac{2}{3}

Step-by-step explanation:

You divide 3 from both sides leaving you with g=(x/3)-(2/3)

Please mark my answer as brainlyest.

7 0
3 years ago
Joshua is 1.45 meters tall. At 2 p.m., he measures the length of a tree's shadow to be 31.65 meters. He stands 26.2 meters away
Lena [83]

Answer:

The height of the tree=8.42 m

Step-by-step explanation:

We are given that

Height of Joshua, h=1.45 m

Length of tree's shadow, L=31.65 m

Distance between tree and Joshua=26.2 m

We have to find the height of the tree.

BC=26.2 m

BD=31.65m

CD=BD-BC

CD=31.65-26.2=5.45 m

EC=1.45 m

All right triangles are similar .When two triangles are similar then the ratio of their corresponding sides are equal.

\triangle ABD\sim \triangle ECD

\frac{AB}{EC}=\frac{BD}{CD}

Substitute the values

\frac{AB}{1.45}=\frac{31.65}{5.45}

AB=\frac{31.65\times 1.45}{5.45}

AB=8.42m

Hence, the height of the tree=8.42 m

6 0
3 years ago
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