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11111nata11111 [884]
3 years ago
7

Every picture except for one has a picture. It will say if it does not have a picture. I will give brainliest to the one who sho

w their work and is correct. This question has 50 points for 50 questions.
What is the volume of the pyramid?
10 cm^3
80 cm^3
120 cm^3
240 cm^3

Which shows how to determine the volume of the pyramid?

V=1/3(12)(8)(10)
V=1/2(12)(10)
V=1/2(12)(8)(10)
V=1/3(12)(10)

Which statements are true about a rectangular pyramid with a height of 9 centimeters and a base with the dimensions of 4 centimeters by 6 centimeters? Check all that apply. (This question does not have a picture!)

The area of the base of the pyramid, B, is 8 cm^2.
The area of the base of the pyramid, B, is 24 cm^2.
A rectangular prism with the dimensions of 9 cm by 4 cm by 6 cm will have 3 times volume of this pyramid.
A rectangular prism with the dimensions of 9 cm by 4 cm by 6 cm will have 1/3 of the volume of this pyramid.
The volume of this pyramid is 72 cm^3.
The volume of this pyramid is 216 cm^3.

If the volume of the pyramid shown is 108 in^3, what is the area of its base?

4 in^2
12 in^2
24 in^2
36 in^2

Which equation should be used to find the volume of the figure?

V= 1/3 (6)(4)(8)
V= 1/2 (6)(4)(8)
V= 1/3 (6)(4)(10)
V= 1/2 (6)(4)(10)

What is the volume of the pyramid in cubic inches?

______in^3

Mathematics
2 answers:
Nataliya [291]3 years ago
8 0
Formula for V of pyramid is V = 1/3 Bh
B = area of base
h = height

Q1.
8 x 6 = 48
48 = area of base
48 x 5 (height) = 240
240 x 1/3 = 80
80 cm^3

Q2.
8 x 12 would get the area of the base.

the formula says 1/3 Bh, so the base is multiplied by the height (10) and by 1/3.
So if you substitute in the values into the formula, it'll be:
V = 1/3 (12) (8) (10)

Q3.
4 x 6 = 24
base = 24 cm^2
height = 9
1/3 x 24 x 9 = 72
Volume = 72 cm^3

statement 1 is incorrect. The area of the base is actually 24 cm^2

statement 2 is correct.

statement 3 is correct. the volume of the rectangular prism (9 x 4 x 6) is 216cm^3, which is 3 times the volume of the pyramid (72 cm^3).

statement 4 is incorrect. This would require the volume of the pyramid to be 9 times of its own volume.

statement 5 is correct.

 statement 6 is incorrect. The volume of the pyramid is 72, not 216.

Q4.
use the balance method to get the answer.
108 / 1/3 = 108 x 3 = 324
324 / 9 (the height) = 36
the base has an area of 36 in^2

Q5.
6 x 4 gets the area of the base
8 is the height
substitute them into the formula:
V = 1/3 (6) (4) (8)

Q6.
8 x 6 = 48
48 = area of base
9 = height
substitute them into the formula:
V = 1/3 (48) (9)
1/3 x 48 x 9 = 144
Volume of this pyramid is 144 in^3
rodikova [14]3 years ago
6 0

Answer:

The answer is 9 cm

Step-by-step explanation:

I am assuming this is the pyramid that has base dimensions of 6 cm and 4 cm. And we are now looking for the height.

The formula for the volume of a pyramid is V= 1/3Bh

Our Base (B) is found by multiplying (6cm)(4cm) = 24 cm^2

Substitute the 24 cm^2 in for B and we now have

V=1/3 (24 cm^2)(h)


We were given a volume of 72 so we will now substitute that value in for V

72 = 1/3 (24 cm^2)(h)

Simplfiy:


72 = 8h

Divide both sides by 8 and we now have a solution of

h=9 cm


Thus our height is 9 cm

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Answer:

a) The expected value is 2.680642

b) The minimun number of newspapers the manager should order is 6.

Step-by-step explanation:

a) Lets call X the demanded amount of newspapers demanded, and Y the amount of newspapers sold. Note that 4 newspapers are sold when at least four newspaper are demanded, but it can be <em>more</em> than that.

X is a random variable of Poisson distribution with mean \mu = 3 , and Y is a random variable with range {0, 1, 2, 3, 4}, with the following values

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we obtain:

PY(0) = ε^(-3) = 0.04978..

PY(1) = ε^(-3)*3^1/1! = 3*ε^(-3) = 0.14936

PY(2) = ε^(-3)*3^2/2! = 4.5*ε^(-3) = 0.22404

PY(3) = ε^(-3)*3^3/3! = 4.5*ε^(-3) = 0.22404

PY(4) = 1- (ε^(-3)*(1+3+4.5+4.5)) = 0.352768

E(Y) = 0*PY(0)+1*PY(1)+2*PY(2)+3*PY(3)+4*PY(4) =  0.14936 + 2*0.22404 + 3*0.22404+4*0.352768 = 2.680642

The store is <em>expected</em> to sell 2.680642 newspapers

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we know that FX(3) = PX(0)+PX(1)+PX(2)+PX(3) = 0.04978+0.14936+0.22404+0.22404 = 0.647231

FX(4) = FX(3) + PX(4) = 0.647231+ε^(-3)*3^4/4! = 0.815262

FX(5) = 0.815262+ε^(-3)*3^5/5! = 0.91608

FX(6) = 0.91608+ε^(-3)*3^6/6! = 0.966489

So, if we ask for 6 newspapers, the probability of receiving at least 6 calls is 0.966489, and the probability to receive more calls than available newspapers will be less than 0.05.

I hope this helped you!

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