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11111nata11111 [884]
3 years ago
7

Every picture except for one has a picture. It will say if it does not have a picture. I will give brainliest to the one who sho

w their work and is correct. This question has 50 points for 50 questions.
What is the volume of the pyramid?
10 cm^3
80 cm^3
120 cm^3
240 cm^3

Which shows how to determine the volume of the pyramid?

V=1/3(12)(8)(10)
V=1/2(12)(10)
V=1/2(12)(8)(10)
V=1/3(12)(10)

Which statements are true about a rectangular pyramid with a height of 9 centimeters and a base with the dimensions of 4 centimeters by 6 centimeters? Check all that apply. (This question does not have a picture!)

The area of the base of the pyramid, B, is 8 cm^2.
The area of the base of the pyramid, B, is 24 cm^2.
A rectangular prism with the dimensions of 9 cm by 4 cm by 6 cm will have 3 times volume of this pyramid.
A rectangular prism with the dimensions of 9 cm by 4 cm by 6 cm will have 1/3 of the volume of this pyramid.
The volume of this pyramid is 72 cm^3.
The volume of this pyramid is 216 cm^3.

If the volume of the pyramid shown is 108 in^3, what is the area of its base?

4 in^2
12 in^2
24 in^2
36 in^2

Which equation should be used to find the volume of the figure?

V= 1/3 (6)(4)(8)
V= 1/2 (6)(4)(8)
V= 1/3 (6)(4)(10)
V= 1/2 (6)(4)(10)

What is the volume of the pyramid in cubic inches?

______in^3

Mathematics
2 answers:
Nataliya [291]3 years ago
8 0
Formula for V of pyramid is V = 1/3 Bh
B = area of base
h = height

Q1.
8 x 6 = 48
48 = area of base
48 x 5 (height) = 240
240 x 1/3 = 80
80 cm^3

Q2.
8 x 12 would get the area of the base.

the formula says 1/3 Bh, so the base is multiplied by the height (10) and by 1/3.
So if you substitute in the values into the formula, it'll be:
V = 1/3 (12) (8) (10)

Q3.
4 x 6 = 24
base = 24 cm^2
height = 9
1/3 x 24 x 9 = 72
Volume = 72 cm^3

statement 1 is incorrect. The area of the base is actually 24 cm^2

statement 2 is correct.

statement 3 is correct. the volume of the rectangular prism (9 x 4 x 6) is 216cm^3, which is 3 times the volume of the pyramid (72 cm^3).

statement 4 is incorrect. This would require the volume of the pyramid to be 9 times of its own volume.

statement 5 is correct.

 statement 6 is incorrect. The volume of the pyramid is 72, not 216.

Q4.
use the balance method to get the answer.
108 / 1/3 = 108 x 3 = 324
324 / 9 (the height) = 36
the base has an area of 36 in^2

Q5.
6 x 4 gets the area of the base
8 is the height
substitute them into the formula:
V = 1/3 (6) (4) (8)

Q6.
8 x 6 = 48
48 = area of base
9 = height
substitute them into the formula:
V = 1/3 (48) (9)
1/3 x 48 x 9 = 144
Volume of this pyramid is 144 in^3
rodikova [14]3 years ago
6 0

Answer:

The answer is 9 cm

Step-by-step explanation:

I am assuming this is the pyramid that has base dimensions of 6 cm and 4 cm. And we are now looking for the height.

The formula for the volume of a pyramid is V= 1/3Bh

Our Base (B) is found by multiplying (6cm)(4cm) = 24 cm^2

Substitute the 24 cm^2 in for B and we now have

V=1/3 (24 cm^2)(h)


We were given a volume of 72 so we will now substitute that value in for V

72 = 1/3 (24 cm^2)(h)

Simplfiy:


72 = 8h

Divide both sides by 8 and we now have a solution of

h=9 cm


Thus our height is 9 cm

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Use the Law of Cosines to find the values of x and y. (PLEASE HELPPP!!!!)
vredina [299]

Answer:

x = 49.8^\circ\\y = 54.6^\circ

Step-by-step explanation:

Kindly refer to the image attached in the answer region for labeling of triangle.

<em>AB </em><em>= 16 </em>

<em>BC </em><em>= 19</em>

<em>AC </em><em>= 15 </em>

\angle ABC = x^\circ\\\angle ACB = y^\circ

We have to find the <em>angles </em><em>x</em> and <em>y</em> i.e. \angle B \text{ and }\angle C.

Formula for <em>cosine rule</em>:

cos B = \dfrac{a^{2}+c^{2}-b^{2}}{2ac}

Where  

<em>a</em> is the side opposite to \angle A,

<em>b</em> is the side opposite to \angle B  and

<em>c</em> is the side opposite to \angle C.

\Rightarrow cos x = \dfrac{19^{2}+16^{2}-15^{2}}{2 \times 19 \times 16}\\\Rightarrow cos x = \dfrac{392}{608} \\\Rightarrow x = 49.8^\circ

Similarly, for finding the value of <em>y:</em>

cos C = \dfrac{a^{2}+b^{2}-c^{2}}{2ab}\\\Rightarrow cos y = \dfrac{19^{2}+15^{2}-16^{2}}{2  \times 19 \times 15}\\\Rightarrow cos y = \dfrac{330}{570}\\\Rightarrow y = 54.6^\circ

Hence, the values are:

x = 49.8^\circ\\y = 54.6^\circ

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