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3 years ago

An angle measures 124° more than the measure of a supplementary angle. What is the measure of each angle?

Mathematics

1 answer:

Alexandra [31]3 years ago

7 0

The measurement of the other angles 56

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Which of the following expressions are equivalent to \left(9\dfrac{7}{8} + 2\dfrac{4}{5}\right)-\dfrac{1}{2}(9 87 +2 54 )− 21

lora16 [44]

Answer:

$12\dfrac{7}{40}$

Step-by-step explanation:

The given expression is

$\left(9\dfrac{7}{8} + 2\dfrac{4}{5}\right)-\dfrac{1}{2}$

We need to find the simplified form of the given expression.

It can be rewritten as

$\left(9+\dfrac{7}{8} + 2+\dfrac{4}{5}\right)-\dfrac{1}{2}$

Combine integers and fractions separately.

$(9+2)+(\dfrac{7}{8}+\dfrac{4}{5}-\dfrac{1}{2})$

Taking LCM we get

$11+\dfrac{35+32-20}{40}$

$11+\dfrac{47}{40}$

In can be written as

$11+\dfrac{40+7}{40}$

$11+1+\dfrac{7}{40}$

$12+\dfrac{7}{40}$

$12\dfrac{7}{40}$

Therefore, the expression $12\dfrac{7}{40}$ is equivalent to the given expression.

5 0

3 years ago

What is the equation of the line that has a slope of 1 and passes through Point (1, 5)

GREYUIT [131]

The equation of this line would be: y= x +4

8 0

3 years ago

Find the area of the triangle below.<br>Be sure to include the correct unit in your answer.<br><br>

OleMash [197]

Answer:

area of triangle= 1/2*h*b

= 1/2*6*16

=3*16

= 48 yd²

This is your answer. If I'm right so,

Please mark me as brainliest. thanks!!!

5 0

3 years ago

Assume that women's heights are normally distributed with a mean given by mu equals 62.5 in,and a standard deviation given by

Misha Larkins [42]

Answer:

(a) 0.5899

(b) 0.9166

Step-by-step explanation:

Let X be the random variable that represents the height of a woman. Then, X is normally distributed with

$\mu$ = 62.5 in

$\sigma$ = 2.2 in

the normal probability density function is given by

$f(x) = \frac{1}{\sqrt{2\pi}2.2}\exp{-\frac{(x-62.5)^{2}}{2(2.2)^{2}}}$ , then

(a) $P(X < 63) = \int\limits_{-\infty}^{63}f(x) dx$ = 0.5899

(in the R statistical programming language) pnorm(63, mean = 62.5, sd = 2.2)

(b) We are seeking $P(\bar{X} < 63)$ where n = 37. $\bar{X}$ is normally distributed with mean 62.5 in and standard deviation $2.2/\sqrt{37}$ . So, the probability density function is given by

$g(x) = \frac{1}{\sqrt{2\pi}\frac{2.2}{\sqrt{37}}}\exp{-\frac{(x-62.5)^{2}}{2(2.2/\sqrt{37})^{2}}}$ , and

$P(\bar{X} < 63) = \int\limits_{-\infty}^{63}g(x)dx$ = 0.9166

(in the R statistical programming language) pnorm(63, mean = 62.5, sd = 2.2/sqrt(37))

You can use a table from a book to find the probabilities or a programming language like the R statistical programming language.

4 0

3 years ago

If 35men can do a piece of work in 45days,How long should 27men takes

Ilya [14]

Answer:

Step-by-step explanation:

what's the difference between 35 and 45 .

5 0

3 years ago